由于使用空格扩展变量，导致Grep错误 [英] Grep error due to expanding variables with spaces

问题描述

我有一个名为"physics 1b.sh"的文件.在bash中，如果我尝试

I have a file called "physics 1b.sh". In bash, if I try

x="physics 1b"
grep "string" "$x".sh

grep抱怨:

grep:  physics 1b: No such file or directory.

但是，当我这样做

grep "string" physics\ 1b.sh 

工作正常.因此，我想问题可能与变量没有扩展到包含grep识别空间所需的反斜杠有关.我如何使它工作?

It works fine. So I guess the problem is something to do with the variable not being expanded to include the backslash that grep needs to recognize the space. How do I get this to work?

使用bash 3.2，mac os 10.6.

Using bash 3.2, mac os 10.6.

没关系，问题是x设置为" physics 1b"，但是当我执行echo $x检查内容时，bash砍掉了前面的空格，所以我无法分辨出它是否不同.上面的第一种方法实际上有效.

Never mind, the problem was that x was set to " physics 1b", but when I did echo $x to check the contents, bash chopped off the spaces in the front so I couldn't tell that it was different. The first way above actually works.

推荐答案

将整个参数放在双引号中:

Put the entire argument in double-quotes:

grep "string" "$x.sh"

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