由于用空格扩展变量导致的 Grep 错误 [英] Grep error due to expanding variables with spaces

问题描述

我有一个名为physics 1b.sh"的文件.在 bash 中，如果我尝试

I have a file called "physics 1b.sh". In bash, if I try

x="physics 1b"
grep "string" "$x".sh

grep 抱怨:

grep:  physics 1b: No such file or directory.

但是，当我这样做时

grep "string" physics 1b.sh 

它工作正常.所以我猜这个问题与变量没有被扩展以包含 grep 需要识别空间的反斜杠有关.我如何让它发挥作用?

It works fine. So I guess the problem is something to do with the variable not being expanded to include the backslash that grep needs to recognize the space. How do I get this to work?

使用 bash 3.2，mac os 10.6.

Using bash 3.2, mac os 10.6.

没关系，问题是 x 被设置为 "physics 1b"，但是当我做 echo $x 检查内容时，bash 砍掉了前面的空格所以我不能说这是不同的.上面的第一种方法确实有效.

Never mind, the problem was that x was set to " physics 1b", but when I did echo $x to check the contents, bash chopped off the spaces in the front so I couldn't tell that it was different. The first way above actually works.

推荐答案

将整个论点放在双引号中:

Put the entire argument in double-quotes:

grep "string" "$x.sh"

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