用grep文件中字符串变量 [英] grep variable string in file

问题描述

我必须在文件中找到字符串：

I must find in a file this string:

200 https://www.example.example

价值200 randomic，我一定要找到每一个HTTP返回code（200前，301，404等...等）

The value 200 is randomic, I must find every HTTP return code (ex 200, 301, 404 etc...etc)

我怎么可以grep仅此字符串返回code变量中（我不想指定grep命令每返回code）？

How can I grep only this string with return code variable (I don't want specify every return code in grep command)?

cat file.txt | grep "*** http*" 

不过，这是行不通的。

But it doesn't work.

推荐答案

所以你要匹配开头的三位数任何线路，其次是HTTP？

So you want to match any line starting with a three digit number, followed by "http"?

grep -E '^[0-9]{3} http' file.txt

更精确由fedorqui（感谢）的建议是这样的：

More accurate as suggested by fedorqui (thanks) would be this:

grep -E '^[1-5][0-9]{2} http' file.txt

这在范围100-599，这是接近HTTP状态codeS的范围相匹配的号码。

This matches numbers in the range 100-599, which is closer to the range of HTTP status codes.

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