从多部分文件上传中将内容读取到内存中 [英] Reading content to the memory from the multi-part file upload
问题描述
我在将上传的XML文件读取到字符串而不是文件时遇到问题.
I have a problem reading uploaded XML file to the string instead of file.
我的问题是,当我尝试访问流(var stream = part.ContentReadStream
)时,它已关闭.我感觉它正在访问关闭的文件流.我是否错误地使用了MultipartFormDataStreamStreamProvider?文件大小只有几千字节,所以应该不会有问题.
My problem is that when I try to access the stream (var stream = part.ContentReadStream
) then it's closed. I have feeling that it is accessing closed file stream. Am I using MultipartFormDataStreamProvider incorrectly? File size is only few kilobytes, so that should not be a problem.
[WebInvoke(Method = "POST", UriTemplate = "{importFile}")]
public HttpResponseMessage Upload(string importFile, HttpRequestMessage request)
{
if (!request.Content.IsMimeMultipartContent())
{
throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
}
// Create a stream provider for setting up output streams
MultipartFormDataStreamProvider streamProvider = new MultipartFormDataStreamProvider();
// Read the MIME multipart content using the stream provider we just created.
var task = request.Content.ReadAsMultipartAsync(streamProvider);
task.Wait();
IEnumerable<HttpContent> bodyparts = task.Result;
string submitter;
if (!bodyparts.TryGetFormFieldValue("submitter", out submitter))
{
submitter = "unknown";
}
// Get list of local file names from stream provider
IDictionary<string, string> bodyPartFileNames = streamProvider.BodyPartFileNames;
var parser = this.parserFactoryFactory.CreateParser();
foreach (var part in bodyparts)
{
using (var stream = part.ContentReadStream)
{
using (var streamReader = new StreamReader(stream))
{
string content = streamReader.ReadToEnd();
var results = parser.Parse(content);
}
}
}
return new HttpResponseMessage(HttpStatusCode.Accepted);
}
这是我的帖子
<h3>Data import test</h3>
<form action="/api/data/Upload" enctype="multipart/form-data" method="POST">
<input type="file" name="importFile"/>
<input type="submit" value="Upload"/>
</form>
推荐答案
解决方案实际上非常简单.当我们不处理文件时,不需要MultipartFormDataStreamProvider.在我的案子上,这个工作相当顺利.
The solution was actually quite simple. MultipartFormDataStreamProvider is not required when we are not dealing with files. This works quite smoothly on my case.
[WebInvoke(Method = "POST", UriTemplate = "{importFile}")]
public HttpResponseMessage Upload(
string importFile, HttpRequestMessage request)
{
if (!request.Content.IsMimeMultipartContent())
throw new HttpResponseException(HttpStatusCode.UnsupportedMediaType);
// Read the MIME multipart content
var task = request.Content.ReadAsMultipartAsync();
task.Wait();
IEnumerable<HttpContent> bodyparts = task.Result;
string submitter;
if (!bodyparts.TryGetFormFieldValue("submitter", out submitter))
submitter = "unknown";
var parser = this.parserFactoryFactory.CreateParser();
foreach (var part in bodyparts)
{
using (var stream = part.ContentReadStream)
{
using (var streamReader = new StreamReader(stream))
{
string content = streamReader.ReadToEnd();
var results = parser.Parse(content);
if (results.IsValid)
// do something
}
}
}
var message = new HttpResponseMessage(HttpStatusCode.Accepted);
return message;
}
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