基于Xamarin中的构建配置，适用于iOS/Android项目的不同的google-services.json/GoogleService-Info.plist` [英] Different `google-services.json/GoogleService-Info.plist` for iOS/Android project based on build configuration in Xamarin

问题描述

所以我有一个要求，我的项目应在Android/iOS上使用不同的GoogleServices文件，同时使用不同的配置，例如在使用调试配置时，它应使用文件的调试版本，而在发行版中，它应使用使用发行版.

So I have a requirement where my project should use different GoogleServices files for Android/iOS while using different configurations like for eg while I am using the debug configuration it should use the debug version of the file and in the release, it should use the release version.

类似于 Xamarin firebase不同的google-services，用于不同构建配置的json

当我按照接受的答案回答时，我会得到一个编译时错误，提示

When I follow the accepted the answer I get a compile-time error saying

命令COPY /Y "$(ProjectDir)GoogleServices\google-services-development.json" "$(ProjectDir)google-services.json"退出，代码为1.

The command COPY /Y "$(ProjectDir)GoogleServices\google-services-development.json" "$(ProjectDir)google-services.json" exited with code 1.

我尝试了清理构建和清理bin/obj的操作.

I tried clean build and cleaning bin/obj nothing changed.

因此，我尝试了此处提到的另一种解决方案，结果是GoogleServices文件(所有文件)都从项目中排除了，如果我构建并运行该文件，则不会发生任何事情.我不确定这是否行得通.

So I tried the other solution mentioned here and what happens is the GoogleServices files(all of them) are excluded from the project and nothing happens if I build and run. I am unsure if this is even working or not.

我在csproj中添加了以下几行，分别用于发布和调试

I have added the following lines in my csproj for release and debug respectively

  <ItemGroup Condition="'$(Configuration)'=='Debug'">
  <GoogleServicesJson Include="Dev\google-services.json">
   <Link>google-services.json</Link>
  </GoogleServicesJson>
  </ItemGroup>

 <ItemGroup Condition="'$(Configuration)'=='Release'">
 <GoogleServicesJson Include="Prod\google-services.json">
  <Link>google-services.json</Link>
 </GoogleServicesJson>
 </ItemGroup>

dev和prod是本机android项目中的根文件夹

Where dev and prod are root folders in my native android project

欢迎提出任何建议.

推荐答案

您必须编辑* .csproj文件.

You have to edit *.csproj file.

使用使用多个Info.plist (LogicalName标记)和条件标记，您可以随心所欲地播放任何其他文件.

Using a solution to use multiple Info.plist (LogicalName tag) and Condition tag you can play with any other files all you want.

对于Android，我将两个* .json文件添加到Resources文件夹中，并将此代码段添加到我的* .csproj文件中:

For Android I added two *.json files to Resources folder and added this snippet to my *.csproj file:

<ItemGroup Condition=" '$(Configuration)' != 'Release' ">
    <GoogleServicesJson Include="Resources\dev-google-services.json">
        <LogicalName>Resources\google-services.json</LogicalName>
    </GoogleServicesJson>
</ItemGroup>
<ItemGroup Condition=" '$(Configuration)' == 'Release' ">
    <GoogleServicesJson Include="Resources\release-google-services.json">
        <LogicalName>Resources\google-services.json</LogicalName>
    </GoogleServicesJson>
</ItemGroup>

在此示例中，我将release-google-services.json用于发布"构建配置，并将dev-google-services.json用于任何其他配置.

In this example I use release-google-services.json for the "Release" build configuration, and dev-google-services.json for any other configurations.

与iOS相同.我在根文件夹中添加了两个* .plist文件，并将此代码段添加到了我的* .csproj文件中:

Same for iOS. I added two *.plist files to root folder and added this snippet to my *.csproj file:

<ItemGroup Condition=" '$(Configuration)' != 'AppStore' ">
    <BundleResource Include="Dev-GoogleService-Info.plist">
        <LogicalName>GoogleService-Info.plist</LogicalName>
    </BundleResource>
</ItemGroup>
<ItemGroup Condition=" '$(Configuration)' == 'AppStore' ">
    <BundleResource Include="Release-GoogleService-Info.plist">
        <LogicalName>GoogleService-Info.plist</LogicalName>
    </BundleResource>
</ItemGroup>

这种方法对我有用.我想您将这些文件放在何处以及如何命名都没有关系.只需使用所需的LogicalName.

This approach works for me. I guess it doesn't matter where you put these files and how you name them. Just use the LogicalName that you need.

此外，您可以将其与其他变量组合以组成更复杂的条件.例如，为了在Release配置中使用不同的* .json文件构建两个* .apk，您可以:

Also, you can combine it with other variables to compose more complicated conditions. For example, in order to build two *.apk in Release configuration with different *.json files you can:

<ItemGroup Condition=" '$(Configuration)|$(DynamicConstants)' != 'Release|' ">
    <GoogleServicesJson Include="Resources\dev-google-services.json">
        <LogicalName>Resources\google-services.json</LogicalName>
    </GoogleServicesJson>
</ItemGroup>
<ItemGroup Condition=" '$(Configuration)|$(DynamicConstants)' == 'Release|' ">
    <GoogleServicesJson Include="Resources\release-google-services.json">
        <LogicalName>Resources\google-services.json</LogicalName>
    </GoogleServicesJson>
</ItemGroup>

像这样构建您的项目:

msbuild MobileApp.sln /p:Configuration=Release /p:DynamicConstants=DEBUG

使用DEBUG参数时，将使用dev-google-services.json构建Release apk.

When you use DEBUG parameter you build Release apk with dev-google-services.json.

省略DEBUG参数时，将使用release-google-services.json构建Release apk.

When you omit DEBUG parameter you build Release apk with release-google-services.json.

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