Yaml到数据库 [英] Yaml to database

问题描述

对于我的c ++程序，我使用jobs.yml，其中包含有关Yaml格式的作业的信息，例如:

For my c++ program, I use jobs.yml which contains information about jobs in yaml format like:

141647523:
  JobType: Turbo
  LocalJobID: 16773779.0
  Status: Done
  SystemPriority: 0.0
  UserPriority: 8.0

然后，我使用 yaml-cpp 库来解析文件并将作业转换为c ++ 对象.由于jobs.yml的大小(〜900Mb)，我无法在程序开始时一次读取所有文件并将其存储在RAM中.

Then I use yaml-cpp library for parsing file and casting jobs to c++ Job objects. Due to the big size of jobs.yml (~900Mb) I can't read all file at once at the beginning of the program and store in RAM.

我如何克服这一障碍? 我想我应该将jobs.yml转换为数据库，并在程序中通过sql请求获得所需的数据?在这种情况下，我该怎么办?

How can I overcome this obstacle? I guess that I should convert jobs.yml to database and in the program get desired data through sql requests? In this case what I should do?

或者也许有更简单的解决方案?

Or maybe there are available more simple solutions?

推荐答案

yaml-cpp具有基于事件的API.只需从YAML::EventHandler派生并使用YAML::Parser.HandleNextDocument.然后在事件处理程序中一对一地处理事件.这样可以避免将整个文件加载到RAM中.

yaml-cpp has an event-based API. Just derive from YAML::EventHandler and use YAML::Parser.HandleNextDocument. Then process the events in your event handler one-by-one. This should save you from loading the whole file into RAM.

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