新>>我将如何读取具有3列且每列包含100个数字的文件的文件? [英] new >> how would i read a file that has 3 columns and each column contains 100 numbers into an array?
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问题描述
int exam1[100];// array that can hold 100 numbers for 1st column
int exam2[100];// array that can hold 100 numbers for 2nd column
int exam3[100];// array that can hold 100 numbers for 3rd column
int main()
{
ifstream infile;
int num;
infile.open("example.txt");// file containing numbers in 3 columns
if(infile.fail()) // checks to see if file opended
{
cout << "error" << endl;
}
while(!infile.eof()) // reads file to end of line
{
for(i=0;i<100;i++); // array numbers less than 100
{
while(infile >> [exam]); // while reading get 1st array or element
???// how will i go read the next number
infile >> num;
}
}
infile.close();
}
推荐答案
int exam1[100];// array that can hold 100 numbers for 1st column
int exam2[100];// array that can hold 100 numbers for 2nd column
int exam3[100];// array that can hold 100 numbers for 3rd column
int main() // int main NOT void main
{
ifstream infile;
int num = 0; // num must start at 0
infile.open("example.txt");// file containing numbers in 3 columns
if(infile.fail()) // checks to see if file opended
{
cout << "error" << endl;
return 1; // no point continuing if the file didn't open...
}
while(!infile.eof()) // reads file to end of *file*, not line
{
infile >> exam1[num]; // read first column number
infile >> exam2[num]; // read second column number
infile >> exam3[num]; // read third column number
++num; // go to the next number
// you can also do it on the same line like this:
// infile >> exam1[num] >> exam2[num] >> exam3[num]; ++num;
}
infile.close();
return 0; // everything went right.
}
我假设您每行总是有3个数字.如果您知道确切的行数,请用0到行数之间的for
替换while.
I assume you always have 3 numbers per line. If you know the exact number of lines, replace the while with a for
from 0 to the number of lines.
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