如何在不指定索引号的情况下用PHP构建对象数组? [英] how to build arrays of objects in PHP without specifying an index number?

问题描述

这是一个奇怪的问题.我正在手动构建对象数组，如下所示:

Here is a weird question. I am building an array of objects manually, like this:

$pages_array[0]->slug = "index";
$pages_array[0]->title = "Site Index";  
$pages_array[0]->template = "interior";

$pages_array[1]->slug = "a";
$pages_array[1]->title = "100% Wide (Layout A)";
$pages_array[1]->template = "interior";

$pages_array[2]->slug = "homepage";
$pages_array[2]->title = "Homepage";
$pages_array[2]->template = "homepage";

我喜欢这是多么的清晰，但是由于我必须指定索引号，因此我无法轻松地重新排列它们.没有索引号怎么办?相关，有什么更好的方法?

I like how clearcut this is, but because I have to specify the index number, I can't rearrange them easily. How can I do this without the index number? Related, what is a better way to do this?

我还尝试通过创建一个类来编写此代码，并让数组上的每个点都成为该类的实例.但是，由于这是一个配置文件，因此很难读取和知道哪个参数与哪个参数一起使用.这就是为什么我在上面选择了这种过时的方法.

I also tried writing this by making a class, and having each spot on the array be instances of that class. But since this is a configuration file, it was hard to read and know what argument went with what parameter. That's why I chose this old-school method above.

任何想法都值得赞赏！

推荐答案

此代码

 $pages_array[1]->slug = "a";

无论如何

都是无效的-如果未正确初始化对象，则会收到严格"警告.因此，您必须以某种方式构造对象-可以使用构造函数:

is invalid anyways - you'll get a "strict" warning if you don't initialize the object properly. So you have to construct an object somehow - either with a constructor:

 $pages_array[] = new MyObject('index', 'title'....)

或使用stdclass强制转换

or using a stdclass cast

 $pages_array[] = (object) array('slug' => 'xxx', 'title' => 'etc')

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