如何在C ++ 11中将元组转换为字节数组 [英] How to convert tuple to byte array in c++11

问题描述

我需要编写一个将元组转换为字节数组的函数. 元组的类型可以包括int, long, double, std::string, char*等. 元组的大小和类型是任意的，例如

I need to write a function to convert tuple to byte array. The type of tuple may include int, long, double, std::string, char*,etc. The size and type of tuple are arbitrary, such as

std:tuple<string, int, double> t1("abc", 1, 1.3);

或

std:tuple<char*, int, int, float, double, string> t2("abc", 1, 2, 1.3, 1.4, "hello");

我想使用这些元组作为输入，并使用字节数组作为返回值.我该怎么办 ?

I want use these tuple as input, and the byte array as return value. What should I do ?

推荐答案

还有出色的 C ++ API 用于消息包，该消息包本身支持元组

There is also the brilliant C++ API for message pack which supports tuples natively

#include <string>
#include <sstream>
#include <tuple>

#include <msgpack.hpp>

int main() {
    auto t = std::make_tuple("1", 1, 1.0);
    auto buffer = std::stringstream{};

    // easy peezy
    msgpack::pack(buffer, t);
    auto tuple_as_string = buffer.str();
}

这篇关于如何在C ++ 11中将元组转换为字节数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！