确定C数组中元素的数量 [英] Determining the quantity of elements in a C array

问题描述

当调用print_array时，int array []参数(计数)的大小不是预期的大小.似乎sizeof 不返回整个数组的大小，即5 * sizeof(int)= 20.

When print_array is called, the size of the int array[] parameter (count) isn't what was expected. It seems sizeof is not returning the size of the entire array which would be 5*sizeof(int) = 20.

namespace Util
{
   void print_array(int array[])
   {
      size_t count = (sizeof array)/(sizeof array[0]);
      cout << count;
      // int count = sizeof(array)/sizeof(array[0]);
      // for (int i = 0; i <= count; i++) cout << array[i];
   }
}


int array_test[5]={2,1,5,4,3};
Util::print_array(array_test);

推荐答案

int array[]在这里变为int* array，而sizeof(array)返回相同的内容sizeof(int*).您需要通过引用传递数组来避免这种情况.

int array[] here becomes int* array, and sizeof(array) returns the same thing sizeof(int*). You need to pass an array by reference to avoid that.

template <size_t N>
void print_array(int (&array)[N]) {
    std::cout << N;
}

int array[] = { 2, 1, 5, 4, 3 };
print_array(array);

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