我如何基于键值将python dict排序到嵌套列表 [英] how can i sort python dict to nested list based on key value
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问题描述
我有一个嵌套的字典
d = {'records':[
{'name':abhi,'age':23,'dept':'cse'},
{'name':anu,'age':20,'dept':'ece'},
{'name':ammu,'age':25,'dept':'cse'},
{'name':anju,'age':26,'dept':'ece'}
]}
但是我想按部门将字典重新排列.我做了不同的方法,但没有得到想要的结果.
but I want to have the dictionary rearranged, grouped by department. I have done different methods, but did not get the desired result.
d = [
[ {'name':abhi,'age':23,'dept':'cse'},
{'name':ammu,'age':25,'dept':'cse'}
],
[ {'name':anu,'age':20,'dept':'ece'},
{'name':anju,'age':26,'dept':'ece'}
]
]
任何帮助将不胜感激.
推荐答案
您所拥有的是词典中的词典列表.您可以使用标准列表排序方法:
What you have is a list of dictionaries within a dictionary. You can sort these dictionaries using standard list sorting methods:
d={'records':[{'name':'abhi','age':23,'dept':'cse'},
{'name':'anu','age':20,'dept':'ece'},
{'name':'ammu','age':25,'dept':'cse'},
{'name':'anju','age':26,'dept':'ece'}]}
d['records'].sort(key = lambda x: x['name'])
>>> d['records']
[{'name': 'abhi', 'age': 23, 'dept': 'cse'}, {'name': 'ammu', 'age': 25, 'dept': 'cse'}, {'name': 'anju', 'age': 26, 'dept': 'ece'}, {'name': 'anu', 'age': 20, 'dept': 'ece'}]
针对您的特定情况:
d['records'].sort(key = lambda x: (x['name'], x['dept']))
然后使用列表理解将具有相同dept
的子列表分组在一起:
And then a list comprehension to group sublists with the same dept
together:
my_list = [[i for i in d['records'] if i['dept'] == de] for de in {i['dept'] for i in d['records']}]
>>> my_list
[[{'name': 'anju', 'age': 26, 'dept': 'ece'}, {'name': 'anu', 'age': 20, 'dept': 'ece'}], [{'name': 'abhi', 'age': 23, 'dept': 'cse'}, {'name': 'ammu', 'age': 25, 'dept': 'cse'}]]
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