C ++无法在用于循环的char数组中打印字母模式 [英] C++ can't print alphabet pattern in char array use for loop

问题描述

我的应用程序的工作是在从用户那里获取文本值之后，该应用程序以水平模式将其打印出来，但没有显示任何内容.

My app's work is after getting text value from user the app print it with pattern horizontally, but it doesn't show any thing.

为使问题更简短，我只输入了26种模式:

for make question shorter i just put 2 patterns of 26:

int main()
{

printf("Please inter a text:");
string input;
cin >> input;

char ptn[2][7][13] = {{
        {' ', ' ', ' ', ' ', ' ', ' ', 'A', ' ', ' ', ' ', ' ', ' ', ' '},
        {' ', ' ', ' ', ' ', ' ', 'A', ' ', 'A', ' ', ' ', ' ', ' ', ' '},
        {' ', ' ', ' ', ' ', 'A', ' ', ' ', ' ', 'A', ' ', ' ', ' ', ' '},
        {' ', ' ', ' ', 'A', 'A', 'A', 'A', 'A', 'A', 'A', ' ', ' ', ' '},
        {' ', ' ', 'A', ' ', ' ', ' ', ' ', ' ', ' ', ' ', 'A', ' ', ' '},
        {' ', 'A', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', 'A', ' '},
        {'A', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', 'A'}},

        {{'B', 'B', 'B', 'B', ' ', ' ',' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {' ', ' ', ' ', ' ', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {'B', ' ', ' ', ' ', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {'B', 'B', 'B', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {'B', ' ', ' ', ' ', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {' ', ' ', ' ', ' ', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '},
        {'B', 'B', 'B', 'B', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' ', ' '}}};

for (int y = 0; y < 7; y++) {
    for (int i = 0; input[i] != '\0'; i++) {
           cout << ptn[input[i]][y];
    }

    cout << "\n";
}
return 0;
}

输出应为:

      A       BBBB                                                                                                              
     A A      B   B                                                                                                             
    A   A     B   B                                                                                                             
   AAAAAAA    BBBB                                                                                                              
  A       A   B   B                                                                                                             
 A         A  B   B                                                                                                             
A           A BBBB 

推荐答案

• ptn[2][7][13]很难理解.在子类型中破坏定义. glyph_set由26个字形组成. glyph由7行组成. row由5列组成(对于空终止符加1):
• ptn[2][7][13] is difficult to understand. Break the definition in subtypes. A glyph_set is made of 26 glyphs. A glyph is made of 7 rows. A row is made of 5 columns (plus 1 for null terminator):

    enum
    {
      col_count = 5 + 1,
      row_count = 7,
      glyph_count = 26
    };

    typedef const char row_t[ col_count ];
    typedef const row_t glyph_t[ row_count ];
    typedef const glyph_t glyph_set_t[ glyph_count ];

• 字形的行由7行5列乘以构成该行的字符数组成.如果您的文字是"AB"，则该行将由7行10列(加上字母之间的空格)组成.
• A line of glyphs is made of 7 rows and 5 columns multiplied by the number of characters the line is made of. If your text is "AB" the line will be made of 7 rows and 10 columns (plus a space between letters).

您的程序(演示):

Your program (demo):

#include <iostream>
#include <string>
#include <cctype>

enum
{
  col_count = 5 + 1,
  row_count = 7,
  glyph_count = 26
};

typedef const char row_t[ col_count ];
typedef const row_t glyph_t[ row_count ];
typedef const glyph_t glyph_set_t[ glyph_count ];
typedef std::string line_t[ row_count ];

glyph_set_t gs
{
  {
    {"  A  "},
    {" A A "},
    {"A   A"},
    {"A   A"},
    {"AAAAA"},
    {"A   A"},
    {"A   A"},
  },

  {
    {"BBBB "},
    {"B   B"},
    {"B   B"},
    {"BBBB "},
    {"B   B"},
    {"B   B"},
    {"BBBB "},
  },
  //...
};


int main()
{
  const char* s = "AB";

  for( int r = 0; r < row_count; ++r )
  {
    for( const char* p = s; *p; ++p )
    {
      int set_idx = std::toupper( *p ) - 'A';
      // this...
      glyph_t& g = gs[ set_idx ];
      std::cout << g[ r ] << ' ';
      // ...or this (whichever is easier for you)
      // std::cout << gs[ set_idx ][ r ] << ' ';
    }
    std::cout << std::endl;
  }
  return 0;
}

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