获取数组每个子数组的最后一个元素 [英] Get the last element of each sub-array of an array

问题描述

我知道对于一个数组，它可以使用下划线的last函数，因此在该数组的情况下为:

I know that for an array it can be used last function of underscore, so in the case of this array it would be:

myArray = [32, 1, 8, 31]; 
lastElement = _.last(myArray);

问题是当存在这样的矩阵时:

The problem is when there is a matrix like this:

myArray = [[1, 3, 5], [55, 66, 77], [0, 1, 2]]; 

所需的结果是

lastElement = [5, 77, 2];

有什么建议吗?

推荐答案

您可以简单地使用

You could simply use Array.from :

var myArray = [[1, 3, 5], [55, 66, 77], [0, 1, 2]]; 

var res = Array.from(myArray, x => x[x.length - 1]);

console.log(res);

此处尚未回答的另一种可能性是 Array#reduce :

Another possibility not already answered here would be Array#reduce :

var myArray = [[1, 3, 5], [55, 66, 77], [0, 1, 2]]; 

var res = myArray.reduce((acc, curr) => acc.concat(curr[curr.length - 1]),[]);

console.log(res);

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