通过内部列表编号对python中的嵌套列表进行排序 [英] Sort a nested list in python by inner list number

问题描述

说我有一个这样的嵌套列表，

say I have a nested list such as this,

[
    ['a', [2, 3, 7]], 
    ['j', [63, 4, 0]], 
    ['c', [1, 155, 10]], 
    ['z', [0, 77, 7]], 
    ['f', [100, 42, 9]]
]

如何按照最里面的列表中选择的最大数字对它进行排序?例如，如果我们要按每个元素列表中从最大到最小的第一个整数对它进行排序，结果将是

How do sort this by the chosen largest number in the innermost list? For instance, if we wanted to sort it by the first integer in each element's list from largest to smallest, the result would be

[
    ['f', [100, 42, 9]], 
    ['j', [63, 4, 0]], 
    ['a', [2, 3, 7]], 
    ['c', [1, 155, 10]], 
    ['z', [0, 77, 7]]
]

推荐答案

您需要使用key提取要进行排序的值；在这里是element[1][0]:

You need to use a key that extracts the value by which to sort; here that is element[1][0]:

sorted(inputlist, key=lambda e: e[1][0], reverse=True)

reverse=True可以从最大到最小排序.

The reverse=True is there to sort from largest to smallest.

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