如何使用PHP对范围内的数字进行分组 [英] How to group numbers in ranges using PHP

问题描述

假设我在数组中具有以下数字序列:

Let's say that I have the following sequence of numbers in an array:

$numbers = array(1,3,2,23,24,25,26, 8)

如何在范围内打印它们，例如:

How can I print them in ranges, for instance:

数字是1-3、23-26、8.

The numbers are 1-3, 23-26, 8.

推荐答案

这是一个简单的版本，创建包含范围的groups

Here's a simple version, creating groups containing your ranges

<?php
$numbers = array(1,3,2,23,24,25,26,8);
sort($numbers);
$groups = array();

for($i = 0; $i < count($numbers); $i++)
{
    if($i > 0 && ($numbers[$i - 1] == $numbers[$i] - 1))
        array_push($groups[count($groups) - 1], $numbers[$i]);
    else // First value or no match, create a new group
        array_push($groups, array($numbers[$i])); 
}

foreach($groups as $group)
{
    if(count($group) == 1) // Single value
        echo $group[0] . "\n";
    else // Range of values, minimum in [0], maximum in [count($group) - 1]
        echo $group[0] . " - " . $group[count($group) - 1] . "\n";
}

输出为

1 - 3
8
23 - 26

现在，如果范围的顺序很重要，就像您在问题中所描述的那样，您仍然可以对组进行排序...据我所知，您希望范围首先是单个值，然后是单个值?这可以通过添加

Now, if the order of your ranges is important, like you described in your question, you can still sort your groups... from what I can see, you want the ranges first followed by the single values? This can be done by adding

function groupRanges($a, $b)
{
    if(count($a) == 1)
        if(count($b) == 1)
            return 0; // equal
        else
            return 1; // so $b is considered less than

    if(count($b) == 1)
        return -1; // so $a is considered less than

    return 0; // both are ranges, keep them there... could be adjusted to compare the size of each range
}

usort($groups, "groupRanges");

就在foreach之前，输出变为:

1 - 3
23 - 26
8

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