排序忽略标点(Java) [英] Sort ignoring punctuation (Java)

问题描述

我正在尝试对Android ListView对象进行排序.我目前正在使用以下代码:

I am trying to sort an Android ListView object. I am currently using the following code:

  // Sort terms alphabetically, ignoring case
  adapter.sort(new Comparator<String>() {
        public int compare(String object1, String object2) {
            return object1.compareToIgnoreCase(object2);
        };

这对我的列表进行排序，而忽略大小写.但是，也最好忽略标点符号.例如:

This sorts my list, whist ignoring case. However, it would be nice to ignore punctuation as well. For example:

c.a.t.
car
cat

应按以下顺序排序:

car
c.a.t.
cat

(两只猫(哪只猫是猫还是c.a.t.)先出现，实际上并不重要，只要它们紧挨着排序即可.)

(It doesn't actually matter which of the two cats (cat or c.a.t.) comes first, so long as they're sorted next to one another).

是否有一种简单的方法可以解决此问题?我认为解决方案包括从字符串中提取字母数字字符，然后进行比较，然后将它们返回到以前的状态，并再次包含非字母数字字符.

Is there a simple method to get around this? I presume the solution would involve extracting JUST the alphanumeric characters from the strings, then comparing those, then returning them back to their former states with the non-alphanumeric characters included again.

推荐答案

比较时，删除不需要的字符

When you compare, remove the characters you don't care about

public int compare(String str1, String str2) {
    String remove = "[\\.:',]"; // change this to all to characters to remoce
    return str1.replaceAll(remove, "").compareToIgnoreCase(object2.replaceAll(remove, ""));
};

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