如何为我的默认范围进行rspec测试 [英] How can i have rspec test for my default scope

问题描述

我的模型具有default_scope(:order =>'created_at') 我的测试(rspec，工厂女孩，shoda等) 是:

my model has default_scope(:order => 'created_at' ) my tests (rspec, factory girl, shoulda, etc.) are:

require 'spec/spec_helper.rb'

describe CatMembership do
  context "is valid" do
    subject { Factory.build(:cat_membership) }
    it { should be_valid }
    it { should belong_to :cat}
    it { should belong_to :cat_group}
    it { should have_db_column(:start_date)}
    it { should have_db_column(:end_date)}
  end
end

推荐答案

我宁愿使用查询并检查结果来进行测试，但是如果您确实必须这样做，那么Rails 3的解决方案可能是这样的:

I would rather have this tested using a query and checking the results, but if you really must do it, one possible solution would be something like this for Rails 3:

CatMembership.scoped.to_sql.should == CatMembership.order(:created_at).to_sql

在Rails 2上:

CatMembership.default_scoping.should == [{:create=>{}, :find=>{:order=>"created_at"}}]

但是我不会说这些解决方案是理想的，因为它们显示了很多实现知识(并且您可以看到实现因不同的Rails版本而异).

But I would not say these solutions are ideal since they show a lot of knowledge of the implementation (and you can see the implementation varies with different Rails versions).

创建示例数据，运行常规的 all 查询并检查结果是否正确排序可能更简单，更接近于实际的单元测试，并且即使升级Rails版本也可以.

Creating sample data, running an usual all query and checking the result is correctly ordered might have been simpler, would be closer to real unit testing and would work even as you upgrade your rails version.

在这种情况下，可能是:

In this case it would possibly be:

before do
  @memberships = []

  @memberships << CatMembership.create!
  @memberships << CatMembership.create!
  @memberships << CatMembership.create!

  [ 1.hour.ago, 5.minutes.ago, 1.minute.ago ].each_with_index do |time, index|
    membership = @memberships[index]
    membership.created_at = time
    membership.save
  end

end

it 'should be correctly ordered' do
  @sorted_memberships = CatMembership.all
  @memberships.first.should == @sorted_memberships.last
  @memberships.second.should == @sorted_memberships.second
  @memberships.third.should == @sorted_memberships.first
end

它更为冗长，但即使您在轨道上向前移动，它也能正常工作.

It's much more verbose, but it's going to work even as you move forward on rails.

现在我刚刚注意到谁问了这个问题:D

And now I have just noticed who asked the question :D

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