Python程序遍历目录并读取文件信息 [英] Python program to traverse directories and read file information

问题描述

我刚刚开始使用Python，但是已经发现它比Bash Shell脚本更具生产力.

I'm just getting started with Python but already have found it much more productive than Bash shell scripting.

我正在尝试编写一个Python脚本，该脚本将遍历从我在其中启动脚本的目录分支的每个目录，并为它遇到的每个文件加载此类的实例:

I'm trying to write a Python script that will traverse every directory that branches from the directory I launch the script in, and for each file it encounters, load an instance of this class:

class FileInfo:

    def __init__(self, filename, filepath):
        self.filename = filename
        self.filepath = filepath

filepath属性将是从根(/)开始的完整绝对路径.这是我希望主程序执行的伪代码模型:

The filepath attribute would be the full absolute path from root (/). Here's the pseudocode mockup for what I'd like the main program to do:

from (current directory):

    for each file in this directory, 
    create an instance of FileInfo and load the file name and path

    switch to a nested directory, or if there is none, back out of this directory

我一直在阅读有关os.walk()和ok.path.walk()的信息，但我想了解一些有关在Python中实现此最直接方法的建议.预先感谢.

I've been reading about os.walk() and ok.path.walk(), but I'd like some advice about what the most straightforward way to implement this in Python would be. Thanks in advance.

推荐答案

我将使用os.walk进行以下操作:

I'd use os.walk doing the following:

def getInfos(currentDir):
    infos = []
    for root, dirs, files in os.walk(currentDir): # Walk directory tree
        for f in files:
            infos.append(FileInfo(f,root))
    return infos

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