如何拆分DistinguishedName? [英] How to Split DistinguishedName?
本文介绍了如何拆分DistinguishedName?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个来自AD的人员及其DN的列表(我无法直接访问该AD).它们的DN格式为:
I have a list of folks and their DN from AD (I do not have direct access to that AD). Their DNs are in format:
$DNList = 'CN=Bob Dylan,OU=Users,OU=Dept,OU=Agency,OU=NorthState,DC=myworld,DC=com',
'CN=Ray Charles,OU=Contractors,OU=Dept,OU=Agency,OU=NorthState,DC=myworld,DC=com',
'CN=Martin Sheen,OU=Users,OU=Dept,OU=Agency,OU=WaySouth,DC=myworld,DC=com'
我想让$DNList
返回以下内容:
OU=Users,OU=Dept,OU=Agency,OU=NorthState,DC=myworld,DC=com
OU=Contractors,OU=Dept,OU=Agency,OU=NorthState,DC=myworld,DC=com
OU=Users,OU=Dept,OU=Agency,OU=WaySouth,DC=myworld,DC=com
推荐答案
我决定将我的评论变成答案:
I decided to turn my comment into an answer:
$DNList | ForEach-Object {
$_ -replace '^.+?(?<!\\),',''
}
这将正确处理作为第一个组件一部分的转义逗号.
This will correctly handle escaped commas that are part of the first component.
我们在字符串开头对一个或多个字符进行了非贪婪匹配,然后查找没有反斜杠开头的逗号(以便该点将与反斜杠和逗号组合匹配并继续进行)
We do a non-greedy match for one or more characters at the beginning of the string, then look for a comma that is not preceded by a backslash (so that the dot will match the backslash and comma combination and keep going).
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