如何在Angular 2中创建到外部URL的链接 [英] How to create a link to external URL in Angular 2
问题描述
我是Angular的新手.我从ver.开始2.
我需要链接到file://...
URL.
我尝试了普通的href
:
I am new to Angular. I am starting with ver. 2.
I need to link to a file://...
URL.
I tried normal href
:
注意:app
是处理应用程序的Web的模型对象.
Note: app
is a model object of the web which deals with applications.
<a target="_blank" href="file://{{app.outputPath}}/index.html">no link here</a>.
那是行不通的-链接在那里,带有正确的URL,但是Angular似乎以某种方式阻止了该事件.为什么?
That doesn't work - the link is there, with correct URL, but Angular seems to block the event somehow. Why?
所以我看过ng-href
,但这是针对Angular 1.x的.而且据我所知,没有*ngHref
.所以这只是一个天真的尝试:
So I've seen ng-href
but that's for Angular 1.x. And there's no *ngHref
from what I can tell. So this was just a naive try:
<a target="_blank" *ngHref="file://{{app.outputPath}}/index.html">over a directive</a>.
我也已经看到了一些有关路由的内容,但似乎仅用于应用程序内部的链接:
Also I have seen something with routing but that appears to be intended only for internal links within the application:
<a [router-link]="['/staticReport', {path: app.outputPath}]">see the report</a>.
app.component.ts:
@RouteConfig([
...
{path:"/staticReport/:path", redirectTo: 'file:// ???? ' }
])
创建外部链接的方式是什么?
What's the way to create an external link?
推荐答案
我假设app
被分配了异步.您可以使用猫王运算符:
I assume app
is assigned async. You can work around this using the Elvis operator:
<a target="_blank" href="file://{{app?.outputPath}}/index.html">no link here</a>.
当Angular在app
实际具有值之前尝试解析绑定时,不会破坏绑定.
to not break the binding when Angular tries to resolve it before app
actually has a value.
原始 例如:
@Component({
selector: 'my-app',
template: `
<h2>Hello {{name}}</h2>
<a target="_blank" [href]="'file://' + outputPath + '/index.html'">no link here</a>
`
})
export class App {
outputPath:string = 'www.google.com';
constructor() {
this.name = 'Angular2';
}
}
实际上,您的第一个示例也很好
Actually, your first example works fine as well
<a target="_blank" href="file://{{outputPath}}/index.html">no link here</a>
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