Python AppIndicator绑定->如何检查菜单是否打开? [英] Python AppIndicator bindings -> howto check if the menu is open?

问题描述

以下是AppIndicator的最小示例:

Here is a minimal example of an AppIndicator:

#!/usr/bin/python

import gobject
import gtk
import appindicator

if __name__ == "__main__":
    ind = appindicator.Indicator("example-simple-client", "gtk-execute", appindicator.CATEGORY_APPLICATION_STATUS)
    ind.set_status (appindicator.STATUS_ACTIVE)
    menu = gtk.Menu()
    menu_items = gtk.MenuItem('Quit')
    menu.append(menu_items)
    menu_items.connect("activate", gtk.main_quit)
    menu_items.show()
    ind.set_menu(menu)
    gtk.main()

不幸的是，有关此文件的信息很不完整.我正在寻找一种检查用户是否打开了AppIndicator菜单的方法(例如，单击了指示器图标).那么打开菜单时会发出信号吗?

Unfortunately the documentation on this is very incomplete. What I'm looking for is a way to check if the AppIndicator menu was opend by the user (e.g. the indicator icon was clicked). So is there a signal, that is emitted when the menu is opened?

推荐答案

不幸的是，答案似乎并非如此.

It looks like the answer is no unfortunately.

print gobject.signal_list_names(ind)
('new-icon', 'new-attention-icon', 'new-status', 'new-label', 'x-ayatana-new-label', 'connection-changed', 'new-icon-theme-path')

我尝试了所有这些，单击指示器后似乎没有一个激活.为了值得一做，统一开发人员似乎希望保持所有指标的行为统一，因此有意对其进行限制是很有可能的.

I tried all of them and none of them appear to activate when the indicator is clicked. For what it's worth the unity devs seem to want to keep all indicators behaving in a uniform way, so it's quite possible that it's deliberately limited.

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