虚拟地球:确定最小/最大可见纬度/经度 [英] VirtualEarth: determine min/max visible latitude/longitude

问题描述

是否有一种简单的方法来确定VirtualEarth地图中的最大和最小可见纬度和经度? 鉴于它不是平坦的表面(VE使用Mercator投影看起来像)，我可以看到数学变得相当复杂，所以我认为有人可能知道要实现这一目标的代码段.

Is there an easy way to determine the maximum and minimum visible latitude and longitude in a VirtualEarth map? Given that it's not a flat surface (VE uses Mercator projection it looks like) I can see the math getting fairly complicated, I figured somebody may know of a snippet to accomplish this.

推荐答案

找到了！ VEMap.GetMapView()返回边界矩形，甚至也适用于3D模式(边界甚至不是矩形).

Found it! VEMap.GetMapView() returns the bounding rectangle, even works for 3D mode as well (where the boundary is not even a rectangle).

var view = map.GetMapView();

latMin = view.BottomRightLatLong.Latitude;
lonMin = view.TopLeftLatLong.Longitude;
latMax = view.TopLeftLatLong.Latitude;
lonMax = view.BottomRightLatLong.Longitude;

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