小词典的散列 [英] Hashing of small dictionary
问题描述
我想散列小词典("dictionaries/small").主文件可以正确编译,但是在运行时,它会生成带有功能insert()
的分段错误" 消息(特别是malloc()
出错,但是我不知道是什么).
I want to hash small dictionary ("dictionaries/small"). Main file compiles correctly, but at runtime it produces "Segmentation fault" message with function insert()
(specifically something wrong with malloc()
, but I don`t know what).
HASH.c
#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
#include <ctype.h>
#include <string.h>
typedef struct node
{
char* name;
struct node* next;
}
node;
node* first[26] = {NULL};
int hash(const char* buffer)
{
return tolower(buffer[0]) - 'a';
}
void insert(int key, const char* buffer)
{
node* newptr = malloc(sizeof(node));
if (newptr == NULL)
{
return;
}
strcpy(newptr->name, buffer);
newptr->next = NULL;
if (first[key] == NULL)
{
first[key] = newptr;
}
else
{
node* predptr = first[key];
while (true)
{
if (predptr->next == NULL)
{
predptr->next = newptr;
break;
}
predptr = predptr->next;
}
}
}
推荐答案
在函数insert()
中,您可以正确分配新节点:
In function insert()
you correctly allocate the new node:
node* newptr = malloc(sizeof(node));
通过这种方式,您可以为完整的结构节点腾出空间:指向node
的指针和指向char
的指针.但是,您不必分配那些指针应该指向的空间.
In this way you make room for a full struct node: a pointer to node
and a pointer to char
. But you don't allocate the space where those pointer are supposed to point.
因此,当您在name
字段中复制输入缓冲区时,您正在执行非法尝试写入尚未分配甚至未初始化的char *
指针:
So, when you copy the input buffer within name
field, you are performing an illegal attempt to write to a char *
pointer that has not been allocated and not even initialized:
strcpy(newptr->name, buffer);
在写入所有指针之前,需要对其进行分配(或至少将其初始化为有效的内存位置).就您而言:
All pointers need to be allocated (or at least initialized to a valid memory location) before writing in them. In your case:
newptr->name = malloc( strlen( buffer ) + 1 );
if( newptr->name )
{
strcpy(newptr->name, buffer);
}
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