在Python中使用Selenium登录gmail [英] Log into gmail using Selenium in Python

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本文介绍了在Python中使用Selenium登录gmail的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用Selenium登录gmail.在新的gmail登录中,首先输入电子邮件ID,然后在下一页输入密码.电子邮件页面的URL和密码页面的URL不同.因此,当我在driver.get中传递密码URL时,它将重新加载页面,并且如果您刷新URL而不输入密码,它将重定向到电子邮件页面.因此,它缺少密码字段选择器. current_url仍然是先前的URL,即电子邮件页面的URL.这是我的代码.我正在使用chrome驱动程序和python 2.X

import os
from selenium import webdriver
from selenium.webdriver.common.keys import Keys

chromedriver = "/Documents/chromedriver" # Path to chrome-driver
os.environ["webdriver.chrome.driver"] = chromedriver
driver = webdriver.Chrome(chromedriver)

# Email insert 

driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin")  #URL of email page
username = driver.find_element_by_id("identifierId")
username.send_keys("myemail")
driver.find_element_by_id("identifierNext").click()


# Password Insert 

driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin")  # URL of password page
password = driver.find_element_by_id("password")
password.send_keys("mypassword")
driver.find_element_by_id("passwordNext").click()

#driver.quit()

解决方案

以下是您的问题的答案:

当我们使用 Python 3.6.1 Selenium 3.4.3 geckodriver v0.17.0 Mozilla Firefox 53.0 一起使用时,我们可以使用定位器 xpath css_selector 通过 Gmail's signin module v2 登录各自的Gmail帐户.


使用XPATH:

以下是使用xpath登录Gmail的示例代码:

from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait

binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")

driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_xpath("//input[@id='identifierId']")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_id("identifierNext").click()
password = WebDriverWait(driver, 5).until(
    EC.element_to_be_clickable((By.XPATH, "//input[@name='password']"))
)
password.send_keys("your_password")
driver.find_element_by_id("passwordNext").click()


使用CSS_SELECTOR:

以下是使用css_selector登录Gmail的示例代码:

from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait

binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")

driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_css_selector("#identifierId")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()
password = WebDriverWait(driver, 5).until(
    EC.element_to_be_clickable((By.CSS_SELECTOR, "input[class='whsOnd zHQkBf'][type='password']"))
)
password.send_keys("your_password")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()

I am trying to log into gmail using Selenium. In the new gmail log in, first you type your email id and then a next page comes where you type your password. URL of email page and password page, both are different. So, when I am passing the password URL in driver.get it is reloading the page and it redirects to email page if you refresh the URL without entering password. Because of this, it is missing the password field selector. current_url is still the previous url, i.e, url of email page. This is my code. I am using chrome driver and python 2.X

import os
from selenium import webdriver
from selenium.webdriver.common.keys import Keys

chromedriver = "/Documents/chromedriver" # Path to chrome-driver
os.environ["webdriver.chrome.driver"] = chromedriver
driver = webdriver.Chrome(chromedriver)

# Email insert 

driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin")  #URL of email page
username = driver.find_element_by_id("identifierId")
username.send_keys("myemail")
driver.find_element_by_id("identifierNext").click()


# Password Insert 

driver.get("https://accounts.google.com/signin/v2/identifier?service=mail&passive=true&rm=false&continue=https%3A%2F%2Fmail.google.com%2Fmail%2F&ss=1&scc=1&ltmpl=default&ltmplcache=2&emr=1&osid=1&flowName=GlifWebSignIn&flowEntry=ServiceLogin")  # URL of password page
password = driver.find_element_by_id("password")
password.send_keys("mypassword")
driver.find_element_by_id("passwordNext").click()

#driver.quit()

解决方案

Here is the Answer to your Question:

When we work with Selenium 3.4.3, geckodriver v0.17.0 and Mozilla Firefox 53.0 using Python 3.6.1, we can use either of the locators xpath or css_selector to log into our respective Gmail accounts through Gmail's signin module v2.


Using XPATH :

Here is the sample code to log into Gmail using xpath:

from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait

binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")

driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_xpath("//input[@id='identifierId']")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_id("identifierNext").click()
password = WebDriverWait(driver, 5).until(
    EC.element_to_be_clickable((By.XPATH, "//input[@name='password']"))
)
password.send_keys("your_password")
driver.find_element_by_id("passwordNext").click()


Using CSS_SELECTOR:

Here is the sample code to log into Gmail using css_selector:

from selenium import webdriver
from selenium.webdriver.firefox.firefox_binary import FirefoxBinary
from selenium.webdriver.common.desired_capabilities import DesiredCapabilities
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait

binary = FirefoxBinary('C:\\Program Files\\Mozilla Firefox\\firefox.exe')
caps = DesiredCapabilities().FIREFOX
caps["marionette"] = True
driver = webdriver.Firefox(capabilities=caps, firefox_binary=binary, executable_path="C:\\Utility\\BrowserDrivers\\geckodriver.exe")

driver.get("https://accounts.google.com/signin")
email_phone = driver.find_element_by_css_selector("#identifierId")
email_phone.send_keys("your_emailid_phone")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()
password = WebDriverWait(driver, 5).until(
    EC.element_to_be_clickable((By.CSS_SELECTOR, "input[class='whsOnd zHQkBf'][type='password']"))
)
password.send_keys("your_password")
driver.find_element_by_css_selector(".ZFr60d.CeoRYc").click()

这篇关于在Python中使用Selenium登录gmail的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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