如何在python中使用硒检查弹出警报 [英] How to check for pop up alert using selenium in python

问题描述

如果要删除的网页中有弹出消息，我要继续下一次迭代.那就是如果有任何弹出消息，我要接受该消息并转到下一个项目，即转到循环的开头.

What I want is to continue with the next iteration if there is a pop up message in the webpage being scrapped. That is if there is any pop up message, I want to accept that message and go to the next item i.e go to the beginning of the loop.

为此，我使用以下代码段:

For this I use the following snippet of code:

from tkinter import *
from tkinter import messagebox as msg
from tkinter import filedialog as fd
from tkinter import ttk
from tkinter import StringVar as sv
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import TimeoutException


for(i in range(0,5)):
      try:
          click_alert=driver.switch_to_alert()
          click_alert.accept()

          continue
      except TimeoutException:
           print('wrong value in'+i+'th row . Please check the value ') 

出现以下错误:

Tkinter回调中的异常

Exception in Tkinter callback

Traceback (most recent call last):
  File "C:\ProgramData\Anaconda3\lib\tkinter\__init__.py", line 1699, in __call__
    return self.func(*args)
  File "C:/Users/chowdhuryr/Desktop/ATT RESEARCH BOT/GUI.py", line 64, in printMessage
    self.Scrapper(str1,str2)
  File "C:/Users/chowdhuryr/Desktop/ATT RESEARCH BOT/GUI.py", line 163, in Scrapper
    click_alert=driver.switchTo().alert()

现在，我非常确定该错误出在click_alert=driver.switch_to_alert()上，因为我已经使用一些健全性检查对其进行了检查.

Now I am pretty certain that the error lies in click_alert=driver.switch_to_alert() because I have checked it using some sanity checks.

推荐答案

通常，我们不会在for后面加上括号.而且，当您打算切换时，警报似乎还不存在. for循环可能只是一个繁忙的等待，使CPU处于循环状态，因此，当警报窗口不存在时，您可以添加一段时间的睡眠，而不仅仅是保持CPU不必要的繁忙. 该代码段可以按以下方式更正:

Normally, we don't put parentheses after a for. And, also, it looks like the alert is not present yet when you intend to switch to. Your for-loop could be just a busy wait keeping CPU busy in your loop, so instead of just keeping CPU unnecessarily busy, you may add a sleep for a while when the alert window is not present yet. The code snippet could be corrected as below:

for i in range(0,5):
    try:
        click_alert=driver.switch_to_alert()
        click_alert.accept()
        continue
    except TimeoutException:
        print('wrong value in'+i+'th row . Please check the value ')
    except NoAlertPresentException:     
        print('i = ', i, 'alert is not present yet, waiting for some time')
        time.sleep(60) # Delay for 1 minute (60 seconds)
    except:
        print "Unexpected error:", sys.exc_info()[0]
        raise   

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