是否存在“让发电机产生所有输出"的简写形式? [英] Is there any shorthand for 'yield all the output from a generator'?

问题描述

是否存在用于以下内容的单行表达式:

Is there a one-line expression for:

for thing in generator:
    yield thing

我尝试yield generator无济于事.

推荐答案

在Python 3.3+中，您可以使用

In Python 3.3+, you can use yield from. For example,

>>> def get_squares():
...     yield from (num ** 2 for num in range(10))
... 
>>> list(get_squares())
[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]

它实际上可以与任何迭代一起使用.例如，

It can actually be used with any iterable. For example,

>>> def get_numbers():
...     yield from range(10)
... 
>>> list(get_numbers())
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> def get_squares():
...     yield from [num ** 2 for num in range(10)]
... 
>>> list(get_squares())
[0, 1, 4, 9, 16, 25, 36, 49, 64, 81]

---

不幸的是，Python 2.7没有等效的结构:'(

---

Unfortunately, Python 2.7 has no equivalent construct :'(

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