如何编写永不产生任何结果的Python生成器函数 [英] How to write Python generator function that never yields anything

问题描述

我想编写一个Python生成器函数，该函数实际上从不产生任何结果.基本上，这是一个什么都不做"的插件，可以由希望调用生成器的其他代码使用(但并不总是需要它的结果).到目前为止，我有这个:

I want to write a Python generator function that never actually yields anything. Basically it's a "do-nothing" drop-in that can be used by other code which expects to call a generator (but doesn't always need results from it). So far I have this:

def empty_generator():
    # ... do some stuff, but don't yield anything
    if False:
        yield

现在，这可以正常工作，但是我想知道是否还有一种更富有表现力的方式来表达同一件事，也就是说，即使函数从不产生任何值，也将其声明为生成器.我上面采用的技巧是向Python显示函数中的yield语句，即使它无法访问.

Now, this works OK, but I'm wondering if there's a more expressive way to say the same thing, that is, declare a function to be a generator even if it never yields any value. The trick I've employed above is to show Python a yield statement inside my function, even though it is unreachable.

推荐答案

另一种方法是

def empty_generator():
    return
    yield

并不是真正的更具表现力"，而是更短. :)

Not really "more expressive", but shorter. :)

请注意，iter([])或简称为[]也可以.

Note that iter([]) or simply [] will do as well.

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