通过索引值按数组中的不同值合并两个数组 [英] Merge two arrays by index value by different value in the array

问题描述

我有两个数组，我想将两个数组的值合并为一个数组，但是两个数组都有不同的值.

I have two arrays and I want to merge the values of the two arrays into a single array, but both arrays have different values.

示例:

var arr1 = [
            { data1: 1 ,data2: "value1"},
            { data1: 1 ,data2: "value2"},
            { data1: 2, data2: "value3"},
            { data1: 3 ,data2: "value3"},
            { data1: 3 ,data2: "value3"}
          ];
var arr2 = [
            { data1:1, data3:"val1"}, 
            { data1: 1, data3: "val2"},
            { data1: 2, data3: "val1"},
            { data1: 3, data3: "val1"},
            { data1: 3, data3: "val2"}
           ]; 
var arr3 = [
             { data1:1, data2: "value1", data3:"val1"}, 
             { data1: 1, data2: "value2", data3: "val2"},
             { data1: 2, data2: "value3", data3: "val1"},
             { data1: 3, data2: "value3", data3: "val1" },
             { data1: 3, data2: "value3", data3: "val2" }
           ];

我尝试过此操作，当data1唯一时可以正常工作，但是问题是当data1重复时它合并了第一个值:

I tried this it, will work fine when data1 is unique, but the problem is when data1 is repeating it merges the first value:

var data = _.map(arr1, function(item){
                return _.extend(item, _.findWhere(arr2, { dataid: item.dataid }));
           });

推荐答案

您可以使用map()并在同一索引上合并第一个和第二个数组的属性.

You can use map() and merge the properties of first and second array on same index.

var arr1 = [ { data1: 1 ,data2: "value1"}, { data1: 1 ,data2: "value2"},{ data1: 2, data2: "value3"}, { data1: 3 ,data2: "value3"}, { data1: 3 ,data2: "value3"} ]; 
var arr2 = [ { data1:1, data3:"val1"}, { data1: 1, data3: "val2"}, { data1: 2, data3: "val1"}, { data1: 3, data3: "val1"}, { data1: 3, data3: "val2"} ];

const res = arr1.map((x,i) => ({...x,...arr2[i]}));
console.log(res)

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