重击案声明 [英] Bash case statement

问题描述

我试图学习案例，就像编写一个功能齐全的脚本一样.

I'm trying to learn case as I was to write a fully functional script.

我从下面开始

#!/bin/sh
case $@ in

    -h|--help)
            echo "You have selected Help"
            ;;
    -B|-b)
            echo "You have selected B"
            ;;
    -C|-c)
            echo "You have selected C"
            ;;
      *)
            echo "Valid Choices are A,B,C"
            exit 1
            ;;
esac

我想使用以下两个选项:

I want to use two of these options:

./getopts.sh -h -c

但是我得到这个结果 有效选择是A，B，C

But i get this result Valid Choices are A,B,C

请您帮忙，让我知道我做错了吗?

Please can you help out and let me know what I'm doing wrong?

我想构建一个脚本，如果您输入一个选项，它将执行某些操作，如果您输入多个选项，则将执行多个操作.

I want to build a script that will do something if you enter one option but do multiple things if you enter multiple.

我还将如何将$ 1解析为该脚本，因为surley我输入的第一个选项(-h)将是$ 1?

Also how would i parse $1 to this script as surley which ever option i enter first (-h) will be $1 ??

谢谢！

推荐答案

尝试一下

#!/bin/sh

usage() {
    echo `basename $0`: ERROR: $* 1>&2
    echo usage: `basename $0` '[-a] [-b] [-c] 
        [file ...]' 1>&2
    exit 1
}


while :
do
    case "$1" in
    -a|-A) echo you picked A;;
    -b|-B) echo you picked B;;
    -c|-C) echo you picked C;;
    -*) usage "bad argument $1";;
    *) break;;
    esac
    shift
done

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