从另一个数组中的重复项中筛选出一个数组 [英] Filter out an array from the duplicates in another array

问题描述

给出以下两个数组:

const array1 = [
                {"id": 1, "color": "black"},
                {"id": 2, "color": "white"},
                {"id": 3, "color": "orange"}
               ];

const array2 = [
                {"id": 2, "color": "white"},
                {"id": 4, "color": "purple"}
               ];

如果在第二个数组中找到重复项，如何将其删除，即结果是:

How could I remove the duplicates from the first array if found in the second, i.e. the result would be:

const filtered = [
                  {"id": 1, "color": "black"},
                  {"id": 3, "color": "orange"}
                 ];

我的代码:

const filtered = array1.map(i => array2.filter(j => i["id"] !== j["id"]))

但它似乎不起作用

推荐答案

要使代码正常工作，您可以使用filter和every

To make your code work you can use filter and every

const array1 = [ {"id": 1, "color": "black"},{"id": 2, "color": "white"},{"id": 3, "color": "orange"}];
const array2 = [{"id": 2, "color": "white"},{"id": 4, "color": "purple"}];

const filtered = array1.filter(i => array2.every(j => i["id"] !== j["id"]))

console.log(filtered)

您可以使用地图和过滤器

You can use Map and filter

const array1 = [ {"id": 1, "color": "black"},{"id": 2, "color": "white"},{"id": 3, "color": "orange"}];
const array2 = [{"id": 2, "color": "white"},{"id": 4, "color": "purple"}];

let mapper = new Map(array2.map(v=> [v.id,v]))

const final = array1.filter(({id})=> !mapper.has(id))

console.log(final)

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