用preg_quote代替preg_replace，但只有一列 [英] preg_replace with preg_quote except one column

问题描述

我正在尝试使用 preg_replace 的一些技巧与 preg_quote 一起使用.

I'm trying to make some tricks with preg_replace used with preg_quote.

我有一个json数据对象数组以及我想要的内容

I have an array of json data object and what I want to

替换除一个键的值之外的所有键的值

Replace all values of keys except the value of one key

下面是输入数组的基本结构:

Below is the basic structure of the input array:

$posts = [{"title":"Test owy post avela","subtitle":"test subtitle",   
           "slug":"test owy-post-laravela-4", "created_at":"2014-11-02"}, 
          {...} ] 

，我需要将tes的所有值替换为<span>tes</span>，除了slug键的值

and I need to replace all values of tes to <span>tes</span> except from slug key's value

下面是生成$posts的代码

$posts = Post::where('title', 'LIKE', '%'.$s.'%')->orWhere('content', 'LIKE', '%'.$s.'%')->get()->toArray();
foreach($posts as &$elm){
     $elm = array_map(function($i) use($s){
          return preg_replace("/(" . preg_quote($s) . ")/is", "<span style='background: #92CF18;'>$1</span>", $i);
     }, $elm);
}

推荐答案

如果您只想将更改应用于"SLUG"以外的所有行，我想这就是您想要的:

If you just want to apply the change for all rows other than "SLUG", I think this is what you want:

$posts = Post::where('title', 'LIKE', '%'.$s.'%')->orWhere('content', 'LIKE', '%'.$s.'%')->get()->toArray();
foreach($posts as &$elm) {
    foreach ($elm as $key => $value)    {
        if ($key != 'SLUG') $elm[$key] = preg_replace("/(" . preg_quote($s) . ")/is", "<span style='background: #92CF18;'>$1</span>", $value);
    }
}

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