php preg_replace 匹配 [英] php preg_replace matches

问题描述

如何访问 preg_replace 中的匹配项作为可用变量?这是我的示例代码:

How do you access the matches in preg_replace as a usable variable? Here's my sample code:

<?php
$body = <<<EOT
Thank you for registering at <!-- site_name -->

Your username is: <!-- user_name -->

<!-- signature -->
EOT;

$value['site_name'] = "www.thiswebsite.com";
$value['user_name'] = "user_123";

$value['signature'] = <<<EOT
live long and prosper
EOT;

//echo preg_replace("/<!-- (#?\w+) -->/i", "[$1]", $body);
echo preg_replace("/<!-- (#?\w+) -->/i", $value[$1], $body);
?>

我不断收到以下错误消息:

I keep getting the following error message:

解析错误:语法错误，意外'$'，期待 T_STRING 或 T_VARIABLE第 18 行

Parse error: syntax error, unexpected '$', expecting T_STRING or T_VARIABLE on line 18

当匹配变量用引号括起来时，上面带有[$i]"的注释行可以正常工作.是不是我遗漏了一些语法?

The above remarked line with "[$i]" works fine when the match variable is enclosed in a quotes. Is there a bit of syntax I'm missing?

推荐答案

像这样:echo preg_replace("/<!-- (#?\w+) -->/", '$1',$body);

顺便说一下，/i 修饰符只会对没有大小写字母的模式造成伤害.

The /i modifier can only do harm to a pattern with no cased letters in it, incidentally.

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