PHP preg_replace特殊字符 [英] PHP preg_replace special characters

问题描述

我想用下划线(_)替换所有非字母和数字字符，例如/&%#$等，并用""空白(所以没有下划线)替换所有'(单引号).

因此，"没有任何"(忽略双引号)将变为" There_wouldnt_be_any ".

我对reg表达式毫无用处，因此在帖子中.

欢呼

解决方案

$newstr = preg_replace('/[^a-zA-Z0-9\']/', '_', "There wouldn't be any");
$newstr = str_replace("'", '', $newstr);

我将它们放在两行中，以使代码更加清晰.

注意:如果您正在寻找Unicode支持，请参阅下面的Filip答案.除了A-z以外，它将匹配所有注册为字母的字符.

I am wanting to replace all non letter and number characters i.e. /&%#$ etc with an underscore (_) and replace all ' (single quotes) with ""blank (so no underscore).

So "There wouldn't be any" (ignore the double quotes) would become "There_wouldnt_be_any".

I am useless at reg expressions hence the post.

Cheers

解决方案

$newstr = preg_replace('/[^a-zA-Z0-9\']/', '_', "There wouldn't be any");
$newstr = str_replace("'", '', $newstr);

I put them on two separate lines to make the code a little more clear.

Note: If you're looking for Unicode support, see Filip's answer below. It will match all characters that register as letters in addition to A-z.

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