PHP使用str_replace和preg_replace [英] PHP Using str_replace along with preg_replace

问题描述

我有一个逗号分隔的值字符串，这些值来自数据库，实际上是图像路径.像这样:

I have a string of comma separated values that comes from a database, which actually are image paths. Like so:

/images/us/US01021422717777-m.jpg,/images/us/US01021422717780-m.jpg,/images/us/US01021422717782-m.jpg,/images/us/US01021422718486-m.jpg

然后，我像下面那样，在,处将它们拆分，并将它们转换为网页的路径.

I then do like below, to split them at the , and convert them into paths for the web page.

preg_replace('~\s?([^\s,]+)\s?(?:,|$)~','<img class="gallery" src="$1">', $a)

效果很好，但是在页面的另一处，我需要将-m更改为-l(这意味着较大)

Works well, but in one place further in my page, I need to change the -m to -l (which means large)

当我像下面那样(将str_replace放在preg_replace内)时，什么也没发生.我该怎么做?

When I do like below (put a str_replace inside the preg_replace), nothing happens. How can I do something like this?

preg_replace('~\s?([^\s,]+)\s?(?:,|$)~','<img class="gallery" src="$1" data-slide="'.str_replace('-m','-l','$1').'">', $a)

推荐答案

您正在将str_replace()调用放在preg_replace()调用的输出模式中.这意味着preg_replace()会将其视为文字文本.

You're putting the str_replace() call in the output pattern for the preg_replace() call. That means preg_replace() is treating it as literal text.

您想要的是这样的

$imgtag = preg_replace(match, replacement, $a);
$imgtag = str_replace('-m','-l',$imgtag);

但是，我认为，如果您更改替换操作的顺序，调试这些内容会更安全，更轻松，例如:

But, in my opinion it would be safer and easier to debug this stuff if you changed the order of your replacement operations, something like this:

foreach ($path in explode(",", $a)) {
  $path = str_replace('-m','-l',$path);
  $imgtag= sprintf ('<img class="gallery" src="%s">', $path);
  /* do something with the $imgtag */
}

这样一来，您不必吹口哨调制解调器:-)即可对该正则表达式进行编程.

That way you don't have to whistle into your modem :-) to program that regexp.

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