异步调用插槽,而无需使用清晰的代码行连接到插槽 [英] Invoke slot asynchronously without connecting to it using clear line of code
问题描述
我遇到了一个怪异的错误-QAction::trigger
导致出现阻塞对话框,这导致我的调用trigger
的服务器卡住(例如,直到对话框关闭后才能处理套接字信号).
I have encountered quite freaky bug - QAction::trigger
caused blocking dialog to appear, which caused my server which called trigger
to go stuck (eg. not able to process socket signals until dialog was closed).
我想出了一种解决方法.我使用Qt::QueuedConnection
将信号void triggerWorkaround()
连接到插槽QAction::trigger
并发出信号:
I figured out a workaround. I connect signal void triggerWorkaround()
to slot QAction::trigger
using Qt::QueuedConnection
and I emit it:
QObject::connect(this, &HackClass::triggerWorkaround, targetAction_.data(), &QAction::trigger, Qt::QueuedConnection);
emit triggerWorkaround();
QObject::disconnect(this, nullptr, targetAction_.data(), nullptr);
但这是三行令人困惑的代码.有没有混淆的方法可以做到这一点?我发现 QMetaObject::invokeMethod
,但是坦率地说,这比我当前的解决方案混乱了10倍.另外,我不想将方法名称用作字符串!
But that's three lines of confusing code. Is there a non-confusing method to do this? I have found QMetaObject::invokeMethod
, but frankly, that's 10 times more confusing than my current solution. Also, I don't want to ever use method name as string!
推荐答案
您可以将其分成函数QueuedInvoke
,如下所示:
You can separate that into a function QueuedInvoke
like this:
//overload for methods/slots
//the slot gets invoked in the thread where the QObject lives
template <typename Object, typename T>
void QueuedInvoke(Object* object, T (Object::* f)()){
QObject signalSource;
QObject::connect(&signalSource, &QObject::destroyed,
object, f, Qt::QueuedConnection);
}
//overload for functors
//the functor gets invoked in the thread where the contextObject lives
//or in the current thread if no contextObject is provided
template <typename Func>
void QueuedInvoke(Func&& f, QObject* contextObject = QAbstractEventDispatcher::instance()){
QObject signalSource;
QObject::connect(&signalSource, &QObject::destroyed,
contextObject, std::forward<Func>(f), Qt::QueuedConnection);
}
这将利用从临时QObject
发出的destroyed()
信号将排队的事件发布到事件循环中.当事件循环处理该事件时,实际上会调用slot/functor.
This will leverage the destroyed()
signal emitted from the temporary QObject
to post a queued event into the event loop. The slot/functor is actually invoked when the event loop processes that event.
因此,您可以像上面那样使用上面的函数,而不是您发布的3行:
So, Instead of the 3 lines you posted, You can use the above function like this:
QueuedInvoke(targetAction_.data(), &QAction::trigger);
我的答案基于关于在给定的QThread
中执行函子的很好的答案.您可以参考它以获取更多详细信息.
My answer is based on this great answer about executing a functor in a given QThread
. You can refer to it for more details.
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