用xsl将XML属性值替换为常量值 [英] Replace xml attribute values with constant values by xsl

问题描述

有XML节点

<svg>
    <g transform="translate(113.63-359.13)">
        <use fill="#f00" xlink:href="#D"/>
        <g transform="translate(72.59-8.504)">
            <use xlink:href="#E"/>
            <path fill="#f00" stroke="#000" stroke-linejoin="round" stroke-linecap="round" stroke-width=".24" d="m6.04 526.26h19.843v4.961h-19.843z"/>
            <use xlink:href="#F"/>
        </g>
        <text x="20.41" y="527.6" fill="#000" font-family="Arial" font-size="8">ProcessOutbound</text>
    </g>
</svg>

可以在此Xpath中找到

which can be found by this Xpath

/svg/g[text="ProcessOutbound"]/use

这也很好

/svg/g[text="ProcessOutbound"]/use/@fill

但是由于某些原因，xsl并未将#f00替换为#00f，这已经让我们感到疲倦了

but for some reasons that xsl is not replaceing #f00 with #00f which is what have tired

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes" encoding="UTF-8"/>
    <xsl:param name="blue" select="'#00f'"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match='/svg/g[text="ProcessOutbound"]/use'>
        <xsl:attribute name='fill'>
            <xsl:value-of select="'$blue'"/>
        </xsl:attribute>
    </xsl:template>

</xsl:stylesheet>

实际上，整个svg文件已复制，但不替换fill属性.我尝试获取一个副本，但替换为填充值

actually the whole svg file is copied but the fill attribute is not replaced. I tried to achive a copy but with the replaced fill value

用xsl将属性值替换为常数值的正确方法是什么?

What is the correct way to replace attribut values with constant values by xsl ?

所以预期结果应该像

   <g transform="translate(113.63-359.13)">
    <use fill="#00f" xlink:href="#D"/>
    <g transform="translate(72.59-8.504)">
        <use xlink:href="#E"/>
        <path fill="#f00" stroke="#000" stroke-linejoin="round" stroke-linecap="round" stroke-width=".24" d="m6.04 526.26h19.843v4.961h-19.843z"/>
        <use xlink:href="#F"/>
    </g>
    <text x="20.41" y="527.6" fill="#000" font-family="Arial" font-size="8">ProcessOutbound</text>
</g>

推荐答案

您的XSLT有一些不正确的地方:

There are a few things incorrect with your XSLT:

• 它正在尝试将整个'use'元素替换为一个属性.
• 您在$blue周围使用两对引号，这导致将其视为字符串.
• 即使您的XML使用名称空间，您也没有使用名称空间.

• It is trying to replace the whole 'use' element with an attribute.
• You are using two pairs of quotes around $blue, which causes it to be treated as a string.
• You are not using namespaces even though your XML uses a namespace.

请尝试以下操作:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns:svg="http://www.w3.org/2000/svg">
    <xsl:output method="xml" indent="yes" encoding="UTF-8"/>
    <xsl:param name="blue" select="'#00f'"/>
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

  <xsl:template match='svg:g[svg:text = "ProcessOutbound"]/svg:use/@fill'>
        <xsl:attribute name='fill'>
            <xsl:value-of select="$blue"/>
        </xsl:attribute>
    </xsl:template>
</xsl:stylesheet>

在示例输入上运行时，结果为:

When run on your sample input, the result is:

<svg xmlns:xlink="...">
    <g transform="translate(113.63-359.13)">
        <use xlink:href="#D" fill="#00f" />
        <g transform="translate(72.59-8.504)">
            <use xlink:href="#E" xmlns:xlink="x" />
            <path fill="#f00" d="m6.04 526.26h19.843v4.961h-19.843z" stroke-width=".24" stroke-linecap="round" stroke-linejoin="round" stroke="#000" />
            <use xlink:href="#F" />
        </g>
        <text font-family="Arial" fill="#000" font-size="8" y="527.6" x="20.41">ProcessOutbound</text>
    </g>
</svg>

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