如何检查编译后的二进制文件是32位还是64位? [英] How can I check if a compiled binary is 32-bit or 64-bit?

问题描述

我有一台运行Lion的Mac，我刚刚下载了最新版本的apache. 我做了平常的事情:

I have a Mac running Lion and I just downloaded latest version of apache. I did the usual things:

$./configure --prefix=/Users/daniels/Sandbox
$ make
$ make install

httpd二进制文件是针对哪种体系结构进行编译的? x86或x64?有没有办法找到这个?

For what architecture is the httpd binary compiled? x86 or x64? Is there a way to find this?

我要寻找的是我想要制作一个类似于MAMP的应用程序，并且希望以某种方式编译Apache，PHP和MySQL，以便将它们放入DMG文件中，然后将其提供给其他人，他们可以运行它.

What I am looking for is that I want to make a MAMP-like application and I want to compile Apache, PHP, and MySQL in such way that I can put them in a DMG file and then give it to other people and they can run it.

推荐答案

签出file命令.

$ file /usr/bin/grep
/usr/bin/grep: Mach-O universal binary with 2 architectures
/usr/bin/grep (for architecture x86_64):    Mach-O 64-bit executable x86_64
/usr/bin/grep (for architecture i386):  Mach-O executable i386

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