如何知道(在脚本中)mac os x中打开了多少个终端? [英] How can I tell (in script) how many Terminals are open in mac os x?

问题描述

我怎么知道当前打开了多少个终端窗口(在Mac OS X中)? 这需要通过shell脚本来完成.

how can I tell how many Terminal windows (in mac os x) are currently opened? this needs to be done from a shell script.

谢谢

推荐答案

此脚本可以满足您的要求，您可以使用osascript从cmd行运行它.

This script does what you ask for, you use osascript to run it from the cmd line.

tell application "Terminal"
    set c to 0
    repeat with i from 1 to (count of windows)
        set c to c + (count of tabs in window i)
    end repeat
    c
end tell

---

由Bavarious编辑:要在外壳程序脚本中使用Adam的AppleScript，您可以执行以下操作:

---

Edit by Bavarious: In order to use Adam’s AppleScript inside a shell script, you can do the following:

#!/bin/bash
read -d '' OSASCRIPT << EOF
    tell application "Terminal"
        set c to 0
        repeat with i from 1 to (count of windows)
            set c to c + (count of tabs in window i)
        end repeat
        c
end tell
EOF

nwindows=$(osascript -e "${OSASCRIPT}")

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