在MySQL和Python中以可重复的方式处理1970年之前的日期 [英] Handling dates prior to 1970 in a repeatable way in MySQL and Python
问题描述
在我的MySQL数据库中,我可以追溯到1700年代中期,我需要以某种类似于Unix时间的格式将其转换为整数. int的值并不重要,只要我可以从数据库或用户输入中获取日期并生成相同的int即可.我需要使用MySQL在数据库端生成int,并使用python从用户那里转换日期.
In my MySQL database I have dates going back to the mid 1700s which I need to convert somehow to ints in a format similar to Unix time. The value of the int isn't important, so long as I can take a date from either my database or from user input and generate the same int. I need to use MySQL to generate the int on the database side, and python to transform the date from the user.
通常, UNIX_TIMESTAMP函数,可以在MySQL中完成此操作,但是对于1970年之前的日期,它始终返回零.
Normally, the UNIX_TIMESTAMP function, would accomplish this in MySQL, but for dates before 1970, it always returns zero.
TO_DAYS MySQL函数也可以,但是我无法从用户输入中获取日期,也无法使用Python创建与该函数在MySQL中创建的值相同的值.
The TO_DAYS MySQL function, also could work, but I can't take a date from user input and use Python to create the same values as this function creates in MySQL.
因此,基本上,我需要一个类似UNIX_TIMESTAMP的函数,该函数可在MySQL和Python中工作,其日期介于1700-01-01和2100-01-01之间.
So basically, I need a function like UNIX_TIMESTAMP that works in MySQL and Python for dates between 1700-01-01 and 2100-01-01.
以另一种方式输入此MySQL伪代码:
Put another way, this MySQL pseudo-code:
select 1700_UNIX_TIME(date) from table;
必须等于此Python代码:
Must equal this Python code:
1700_UNIX_TIME(date)
推荐答案
I don't have MySQL here installed, but when I look here: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_to-days - I see an example TO_DAYS('2008-10-07')
returning 733687.
以下Python函数返回datetime(2008,10,7).toordinal()
= 733322,比MySQL的输出少365.
The following Python function returns datetime(2008,10,7).toordinal()
= 733322, which is 365 less than the MySQL's output.
因此,请采取以下措施:
So take this:
from datetime import datetime
query = '2008-10-07'
nbOfDays = datetime.strptime(query, '%Y-%m-%d').toordinal() + 365
,它应该可以在1700年到2100年之间使用日期.
and it should work for dates between 1700 and 2100.
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