在OSX上使用格式语言的德语数字分隔符? [英] German number separators using format language on OSX?

问题描述

我想根据德语编号约定格式化整数和浮点数.使用格式语言和演示文稿类型n，这是可能的，但在我的平台上失败.

I want to format integer and float numbers according to the German numbering convention. This is possible using the format language and the presentation type n but fails on my platform.

• 平台:OS X 10.8.2(Mountain Lion)
• Python:2.7.3 64位(v2.7.3:70274d53c1dd, Apr 9 2012, 20:52:43) [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin

示例:

• 1234 => 1.234
• 1234.56 => 1.234,56
• 1000000 => 1.000.000

• 1234 => 1.234
• 1234.56 => 1.234,56
• 1000000 => 1.000.000

到目前为止我尝试过的事情:

What I have tried so far:

1. 设置德语语言环境

1. Setting the German locale

import locale
locale.setlocale(locale.LC_ALL, 'de_DE')

格式说明选项,仅识别英语格式.

The format specification option , only recognizes the English format.

'{:,}'.format(1234)
'1,234'

'{:,}'.format(1234.56)
'1,234.56'

'{:,}'.format(1000000)
'1,000,000'

根据 Python文档，整数和浮点表示类型n应该可以执行我想要的操作，但是不可以.

According to the Python docs, the integer and float presentation type n is supposed to do what I want but it doesn't.

 '{:n}'.format(1234)
 '1234'

 '{:n}'.format(1234.56)
 '1234,56'  # at least the comma was set correctly here

 '{:n}'.format(1000000)
 '1000000'

 '{:n}'.format(12345769.56)
 '1,23458e+07'  # it's doing weird things for large floats

受@ J.F.Sebastian启发的更多示例和比较:

Some more examples and comparisons inspired by @J.F.Sebastian:

for n in [1234, 1234.56, 1000000, 12345769.56]:
    print('{0:,} {0:n}'.format(n))
    fmt, val = "%d %f", (n, n)
    print(fmt % val)
    print(locale.format_string(fmt, val))
    print(locale.format_string(fmt, val, grouping=True))
    print('-'*60)

这会在我的平台上产生以下错误结果:

This yields the following incorrect results on my platform:

    1,234 1234
    1234 1234.000000
    1234 1234,000000
    1234 1234,000000
    ------------------------------------------------------------
    1,234.56 1234,56
    1234 1234.560000
    1234 1234,560000
    1234 1234,560000
    ------------------------------------------------------------
    1,000,000 1000000
    1000000 1000000.000000
    1000000 1000000,000000
    1000000 1000000,000000
    ------------------------------------------------------------
    12,345,769.56 1,23458e+07
    12345769 12345769.560000
    12345769 12345769,560000
    12345769 12345769,560000
    ------------------------------------------------------------

我没有得到的正确结果如下:

The correct results which I'm not getting would look like that:

    1,234 1.234
    1234 1234.000000
    1234 1234,000000
    1.234 1.234,000000
    ------------------------------------------------------------
    1,234.56 1.234,56
    1234 1234.560000
    1234 1234,560000
    1.234 1.234,560000
    ------------------------------------------------------------
    1,000,000 1.000.000
    1000000 1000000.000000
    1000000 1000000,000000
    1.000.000 1.000.000,000000
    ------------------------------------------------------------
    12,345,769.56 1,23458e+07 
    12345769 12345769.560000
    12345769 12345769,560000
    12.345.769 12.345.769,560000
    ------------------------------------------------------------

您仅使用格式语言对我有解决方案吗?有什么办法欺骗我平台上的语言环境设置以接受分组?

Do you have a solution for me using the format language only? Is there any way to trick the locale settings on my platform to accept grouping?

推荐答案

超级丑陋，但从技术上讲可以回答以下问题:

Super ugly, but technically answers the question:

来自 PEP 378 :

'{:,}'.format(1234.56).replace(",", "X").replace(".", ",").replace("X", ".")
'1.234,56'

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