Webview loadRequest不起作用 [英] Webview loadRequest not working

问题描述

在我的应用程序中，我正在使用Webview根据用户的首选语言加载网站的不同版本.为此使用WebFrame的loadRequest方法-

In my application, i'm using a Webview to load different versions of a website based on user's preferred language.Using WebFrame's loadRequest method for this -

[[aWebView主机] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:aStr]]];

[[aWebView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:aStr]]];

如果aStr仅包含英文字母，即aStr = http://....../language/English，则其正常工作&网页加载.但是，如果aStr是http://....../language/ウンウンウン(日语)之类的东西，则什么也不会发生，WebView不会加载，也不会引发任何错误.如果我将相同的链接粘贴到Safari中，则网页会加载到那里.关于如何解决此问题有什么建议吗?

If, aStr contains english alphabets only,i.e if aStr = http : // ....../language/English ,then its working fine & the webpage loads. But if aStr is something like http: //....../language/ウンウンウン(Japanese), nothing happens, neither WebView loads, nor it throws any error. If i paste the same link in Safari, the webpage loads there. Any suggestion on how to fix this issue?

我也尝试了[aWebView setMainFrameURL:aStr]方法.那里也有同样的问题.

I've also tried [aWebView setMainFrameURL:aStr] method. Same issue there too.

推荐答案

您必须先转义aStr中的无效URL字符，然后才能使用它使用[aStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]创建NSURL.

You have to escape the invalid URL characters in aStr before you can use it to create the NSURL using [aStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding].

//Encode invalid URL characters
aStr = [aStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]
[[aWebView mainFrame] loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:aStr]]];

如果字符串无效，则

URLWithString:返回nil值.这就是为什么您的UIWebView没有错误并且不加载任何内容的原因.

URLWithString: returns a nil value if the string is invalid. Which is why you your UIWebView has no error and does not load anything.

这篇关于Webview loadRequest不起作用的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！