在python脚本中调用bash函数 [英] Call a bash function within a python script

问题描述

我有一个python脚本(例如test.py)和一个commands.txt文件，其中包含一个自定义bash函数(例如my_func)以及其参数(例如

I have a python script (e.g. test.py) and a commands.txt file which contains a custom bash function (e.g. my_func) along with its parameters, e.g.

my_func arg1 arv2; my_func arg3 arg4; my_func arg5 arg6;

此功能包含在~/.bash_profile中. 我试图做的是:

This function is included in the ~/.bash_profile. What I have tried to do is:

subprocess.call(['.', path/to/commands.txt], shell=True)

就将shell参数设置为True而言，我知道这不是最好的情况，但是即使这样，我似乎也无法实现它.运行test.py时得到的是: my_func: command not found

I know this is not the best case, in terms of setting the shell argument into True, but I cannot seem to implement it even in this way. What I get when I run test.py is: my_func: command not found

推荐答案

您将需要直接调用bash，并指示其处理两个文件.

You will need to invoke bash directly, and instruct it to process both files.

在命令行上，这是:

bash -c '. ~/.bash_profile; . commands.txt'

用python包装它:

Wrapping it in python:

subprocess.call(['bash', '-c', '. ~/.bash_profile; . commands.txt'])

您也可以在commands.txt顶部找到〜/.bash_profile.这样您就可以运行一个文件.

You could also source ~/.bash_profile at the top of commands.txt. Then you'd be able to run a single file.

将函数提取到一个单独的文件中可能是有意义的，因为.bash_profile是供登录shell使用的，而不是这样.

It may make sense to extract the function to a separate file, since .bash_profile is intended to be used by login shells, not like this.

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