将单个视频输入文件分割为30秒的块 [英] Split single video input files into 30 second blocks

问题描述

我正在尝试将几个视频文件(.mov)分成30秒的块.

I am trying to split several video files (.mov) into 30 second blocks.

我不需要指定30秒的开始或结束时间.

I do not need to specify where the 30 seconds start or finish.

示例-单个45秒的视频(VID1.mov)将被分为VID1_part1.mov(30秒)，VID1_part2.mov(15秒).理想情况下，我也可以删除音频.

EXAMPLE- A single 45 second video (VID1.mov) will be split into VID1_part1.mov (30 seconds), VID1_part2.mov (15 seconds). Ideally, I can remove audio too.

我尝试使用bash(osx)，但未成功.它没有将视频分成多个部分-而是似乎只是在修改原始文件(并将其长度缩短为1-2秒):

I made an attempt, using bash (osx), but was unsuccessful. It did not split the video into multiple parts- instead it just seemed to modify the original file (and made it into a length of 1-2 seconds):

find . -name '*.mov' -exec ffmpeg -t 30 -i \{\} -c copy \{\} \;

推荐答案

您可以为此使用FFmpeg的分段混合器.

You can use FFmpeg's segment muxer for this.

ffmpeg -i input -c copy -segment_time 30 -f segment input%d.mov

取决于视频关键帧的位置，每个片段都不会以mod 30秒开始.您必须为此省略-c copy.

Depending on where the video keyframes are, each segment won't start at mod 30 secs. You'll have to omit -c copy for that.

此外，FFmpeg不执行就地编辑.您的bash脚本似乎也显示输出的输入名称.那行不通.

Also, FFmpeg does not do in-place editing. Your bash script seems to present the input name for output as well. That won't work.

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