在Mac终端中-如何从stdin获取箭头键? [英] In the mac terminal - how can I get arrow keystrokes from stdin?

问题描述

我想用箭头键(例如bash'dialog')浏览终端对话框菜单

I'd like to browse a terminal dialog menu with the arrow keys (like bash 'dialog')

我希望使用ruby解决方案，但是bash/python可以工作.

I would prefer ruby solution, but bash/python could work.

read -n1 input # is not good enough, cause the arrow keys are not regular chars.

此外，mac术语中的读取"不支持小于1秒的超时.

Also, the 'read' in mac term doesn't support smaller timeout than 1 second.

有什么事吗?

谢谢

推荐答案

我不确定您在寻找什么-

I am not sure what you are looking for -

1. 模拟对应用程序的按键操作的方法，或
2. 一种生成简单对话框的方法，或
3. 从键盘读取字符的方法...

但是，这些可能会给您一些想法:

However, these may give you some ideas:

对于1 :您可能需要查看Automator和Applescript

For 1: You would probably need to look at the Automator and Applescript

tell application "System Events" to tell process "Finder"
   click menu item "New Finder Window" of menu 1 of menu bar item "File" of menu bar 1
end tell

对于2 :您可以查看Platypus，以在脚本周围生成对话框和包装-在此处可用

For 2: You could look at Platypus for generating dialog boxes and wrappers around scripts - available here

对于3 :以下内容可能会做您想要的事情

For 3: The following may do something like you want

#!/bin/bash
#
# Read a key in cbreak mode
stty cbreak -echo; KEY=$(dd bs=1 count=1 2>/dev/null); stty -cbreak echo
#
# If ESCAPE, read next part
if [ $KEY = $'' ]; then
   stty cbreak -echo; KEY=$(dd bs=1 count=1 2>/dev/null); stty -cbreak echo
   stty cbreak -echo; KEY=$(dd bs=1 count=1 2>/dev/null); stty -cbreak echo
   [ $KEY = "A" ] && echo UP
   [ $KEY = 'B' ] && echo DOWN
   [ $KEY = 'C' ] && echo RIGHT
   [ $KEY = 'D' ] && echo LEFT
   exit
fi
echo $KEY

我应该解释if [ $KEY行需要输入

if [ $KEY = $'CONTROL-V ESCAPE' ]

即输入这5件事

$
single quote
Control V
Escape
single quote

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