如何避免PHP中的调用时不通过引用传递错误? [英] How to avoid call-time pass-by-reference deprecated error in PHP?

问题描述

我正在尝试减少发送到我的Apache服务器日志中的警告.

一个警告是:

不推荐使用呼叫时间传递.

Call-time pass-by-reference has been deprecated.

我很难想象为什么不赞成使用它，因为它是一种有用的编程功能，基本上，我这样做:

It is hard for me to imagine why this was deprecated since it is such a useful programming feature, basically I do this:

public function takeScriptsWithMarker(&$lines, $marker) {

    ...
}

，我反复调用此函数，从结果中获取结果并进行处理，但也通过重复发送该方法使数组$ lines建立起来.

and I call this function repeatedly getting results back from it and processing them but also letting the array $lines build up by being sent into this method repeatedly.

1. 要重新编程，这将是很广泛的.
2. 我不想只是关闭警告"，因为我想查看其他警告.

因此，不赞成使用按引用调用，实现此模式的功能的可接受方式"是什么:即将字符串数组发送到方法中，让它们成为方法改变了，然后继续使用该数组?

So, as call-by-reference is deprecated, what is the "accepted way" to attain the functionality of this pattern: namely of sending an array of strings into a method, have them be changed by the method, then continuing to use that array?

推荐答案

实际上，定义函数的方式没有问题.调用函数的方式有问题.因此，对于您的示例，不必像这样调用它:

Actually, there's no problem with the way you define the function. Is a problem with the way you call the function. So for your example, instead of calling it like:

takeScriptsWithMarker(&$lines, $marker);

您可以这样称呼它:

takeScriptsWithMarker($lines, $marker); // no ampersands :)

因此该功能仍然可用.但我不知道此更改的原因.

So the feature is still available. But I don't know the reason behind this change.

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