不通过引用传递简单类型的原因？ [英] Reasons to not pass simple types by reference?

问题描述

据我所知，你不应该通过引用在c ++中传递简单的类型，因为它不会提高性能，它甚至不利于性能（？）。至少这是我从网上收集的。

So far as I understand you should not pass simple types by reference in c++ because it does not improve perfomance, it's even bad for performance(?). At least thats what I managed to gather from the net.

但我找不到 reason 为什么它对性能有害，因为c ++只是创建一个新的简单类型比查找变量或它是什么更快？

But I can't find out the reason why it's bad for performance, is it because it's quicker for c++ to just create a new simple type than it it is too look up variable or what is it?

推荐答案

如果你创建一个引用，它是：

If you create a reference, it's:

pointer to memory location -> memory location

如果使用值，则为：

memory location

复制任何一种方式（引用或值），通过引用传递不会提高性能;必须进行一次额外的查找。所以它理论上恶化的表现，但不是任何金额你会注意到。

Since a value has to be copied either way (the reference or the value), passing by reference does not improve performance; one extra lookup has to be made. So it theoretically "worsens" performance, but not by any amount you'll ever notice.

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