jQuery的.end()在.contents()之后不能按预期工作吗? [英] jQuery's .end() doesn't work as expected after .contents()?

问题描述

a = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").remove().end().text()
b = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").text()
c = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").empty().end().text()
d = $("table").clone().text()

$("#a").text(a)
$("#b").text(b)
$("#c").text(c)
$("#d").text(d)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
  <tbody>
    <tr>
      <td>Foo</td>
      <td>
        <p>
          <span><input type="checkbox" disabled="disabled">1</span>
          <span><input type="checkbox" disabled="disabled" checked="checked">2</span>
          <span><input type="checkbox" disabled="disabled">3</span>
        </p>
      </td>
    </tr>
  </tbody>
</table>

A: <span id="a"></span><br/>
B: <span id="b"></span><br/>
C: <span id="c"></span><br/>
D: <span id="d"></span><br/>
EXPECTED: Foo 2

我的逻辑是找到删除<p>中除已选中<input>的<span>之外的所有内容.然后打印出修改后的HTML的.text().

My logic is to find remove everything inside <p> EXCEPT for the <span> that has the checked <input>. Then print out the .text() of that modified HTML.

我知道jQuery语句部分正确，因为b正确选择了应该删除的两个选项，即1和3.只是不确定如何仅使jQuery输出Foo 2.

I know the jQuery statement is partially correct since b correctly selects the two options that should be removed, ie 1 and 3. Just not sure how to make jQuery output Foo 2 only.

我认为.end()将退出" .find()，但事实并非如此.我该如何纠正呢?还是有更好的方法呢?

I assume .end() will "exit out" of the .find(), but it's not. How do I correct this or is there a better way to do this?

最后，我需要没有(匿名)功能的单行jQuery语句，因为我使用的工具仅支持单行jQuery语句.嵌套很好，即$("foo").find($("bar")).我最终只想提取此HTML的.text()，因此我想删除未检查其相应输入的文本.

Lastly, I need a one-line jQuery statement without (anonymous) functions, since the tool I'm using only supports one-liner jQuery statements. Nesting is fine, ie $("foo").find($("bar")). I eventually just want to extract the .text() of this HTML, hence I want to remove the text whose respective input isn't checked.

推荐答案

我是通过反复试验随机发现的.原来我需要三个.end()通话.

I randomly found out by trial-and-error. It turns out I needed three .end() calls.

我猜一个关闭.not()，一个关闭.contents，最后一个关闭.find() ???

I guess one closes the .not(), one closes the .contents, and the last one closes the .find()???

a = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").remove().end().text()
b = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").text()
c = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").empty().end().text()
d = $("table").clone().text()
answer = $("table").clone().find("p:has(input)").contents().not("span:has(input:checked)").empty().end().end().end().text()

$("#a").text(a)
$("#b").text(b)
$("#c").text(c)
$("#d").text(d)
$("#answer").text(answer)

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<table>
  <tbody>
    <tr>
      <td>Foo</td>
      <td>
        <p>
          <span><input type="checkbox" disabled="disabled">1</span>
          <span><input type="checkbox" disabled="disabled" checked="checked">2</span>
          <span><input type="checkbox" disabled="disabled">3</span>
        </p>
      </td>
    </tr>
  </tbody>
</table>

A: <span id="a"></span><br/>
B: <span id="b"></span><br/>
C: <span id="c"></span><br/>
D: <span id="d"></span><br/>
EXPECTED: Foo 2<br/>
ANSWER: <span id="answer"><span>

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