RecycleView的跨度大小 [英] RecycleView's span size

问题描述

我正在尝试实现与上图类似的布局 与RecyclerView和GridLayoutManager一起使用时，我尝试根据位置设置setSpanSizeLookup，但无法模仿上面的设计.

I'm trying to achieve a layout similar to the picture above with the RecyclerView in conjunction with the GridLayoutManager, i tried setting the setSpanSizeLookup based on position but couldn't mimic the design above..

有人可以帮忙吗?

    mRecyclerView = (RecyclerView) contentView;
    mRecyclerView.setHasFixedSize(false);

    GridLayoutManager gridLayoutManager = new GridLayoutManager(getActivity(), 3);
    gridLayoutManager.setSpanSizeLookup(new GridLayoutManager.SpanSizeLookup() {
        @Override
        public int getSpanSize(int position) {
            return 3 - (position % 3);
        }
    });

    mRecyclerView.setLayoutManager(gridLayoutManager);

..

我得到的是什么

What i'm getting

推荐答案

好，您希望将交替的行"平均分配给两个单元格.均匀分割需要偶数列，而3不是偶数.因此，将其更改为2.

Well, you want alternate "rows" to be evenly split between two cells. Evenly split requires an even number of columns, and 3 is not an even number. So, change that to 2.

现在，您希望getSpanSize()返回(按行):

Now, you want getSpanSize() to return (by row):

• 位置0 = 2(即跨越两个单元格)
• 位置1和2 = 1(即每个位置占用一个单元格)
• 位置3 = 2
• 位置4和5 = 1
• 等

(position % 3) > 0 ? 1 : 2似乎可以为您提供.

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