Firebase Storage getDownloadUrl()“不是函数"； [英] Firebase Storage getDownloadUrl() "is not a function"

问题描述

let storage = firebase.storage();
let storageRef = storage.ref("EnglishVideos/" + movieTitle + "/" + movieTitle + "_full.mp4");
    console.log(storageRef); // looks OK, no error messages

上面的代码有效，从Firebase存储返回的对象具有正确的位置，没有错误消息.

The above code works, the object returned from Firebase Storage has the correct location, no error messages.

但是getDownloadUrl()不起作用:

let myURL = storageRef.getDownloadUrl();
console.log(myURL); // TypeError: storageRef.getDownloadUrl is not a function

错误为TypeError: storageRef.getDownloadUrl is not a function.似乎是原型链错误.我正在使用AngularJS，也许我没有在控制器中注入必要的依赖项?我将$firebaseStorage注入到控制器中，但没有帮助.我从此控制器对Firebase Realtime Database的调用工作正常.

The error is TypeError: storageRef.getDownloadUrl is not a function. It seems like a prototype chain bug. I'm using AngularJS, maybe I didn't inject a necessary dependency into my controller? I injected $firebaseStorage into the controller but it didn't help. My calls to Firebase Realtime Database from this controller are working fine.

推荐答案

它是getDownloadURL，而不是getDownloadUrl.大写.我的工作代码是

It's getDownloadURL, not getDownloadUrl. Capitalization. My working code is

var storageRef = firebase.storage().ref("EnglishVideos/" + movieTitle + "/" + movieTitle + "_full.mp4");
  storageRef.getDownloadURL().then(function(url) {
    console.log(url);
  });

"官方版本是

var storageRef = firebase.storage.ref("folderName/file.jpg");
storageRef.getDownloadURL().then(function(url) {
  console.log(url);
});

请注意，在storage之后需要一个()，即storage().

Note that I needed a () after storage, i.e., storage().

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