Firebase refFromURL不是函数 [英] Firebase refFromURL is not a function

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本文介绍了Firebase refFromURL不是函数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用HTML表中的Javascript从Firebase存储中获取一些图像,但是我一直收到此错误:

I'm trying to get some images from Firebase storage using Javascript in an HTML table, but I keep getting this error:

storage.refFromURL is not a function

考虑到此处中的信息,这很奇怪>

Which is weird, considering the information from here

///从Google Cloud Storage URI创建引用 var gsReference = storage.refFromURL('gs://bucket/images/stars.jpg')

// Create a reference from a Google Cloud Storage URI var gsReference = storage.refFromURL('gs://bucket/images/stars.jpg')

javascript代码也从Firebase数据库获取数据,并且数据库中的每个子级都以 gs://xxxxxxx的形式包含指向Firebase存储的URL(在db中定义为imageUrl). ,我想在表格中使用.换句话说,我想从数据库中获取文本,从存储中获取图像,但是我一直收到"not a function"错误.我有以下代码:

The javascript code gets data from a Firebase database as well, and each child in the database contains an URL (defined in the db as imageUrl) to a Firebase storage in the form of gs://xxxxxxx, which I would like to use in a table. In other words, I would like to have the text from a database, and the image from storage, but I keep getting the "not a function" error. I have the following code:

index.js

var rootRef = firebase.database().ref().child("Test");
var storage = firebase.storage().ref();

rootRef.on("child_added", snap => {
  var headline = snap.child("headline").val();
  var url_ul = snap.child("imageUrl").val();

  var storageRef = storage.refFromURL('url_ul').getDownloadURL().then(function(url) {
    var test = url;
    alert(url);
    document.querySelector('img').src = test;
  }).catch(function(error) {});

  $("#table_body").append("</td><td>" + headline + "</td><td><img src='test' alt='' border=3 height=100 width=100></td>");
});

以及包含Firebase信息的HTML文件:

And the HTML file which contains the Firebase information:

<!DOCTYPE html>
<html>

<head>
  <title>Firebase Web Basics</title>
  <link href="https://fonts.googleapis.com/css?family=Raleway:300,400,500,700" rel="stylesheet">
  <script src="https://use.fontawesome.com/939e9dd52c.js"></script>
</head>

<body>
  <div class="mainDiv" align="left">
    <h1>All users</h1>
    <table>
      <thead>
        <tr>
          <td>Headline</td>
          <td>Image</td>

        </tr>
      </thead>
      <tbody id="table_body">
      </tbody>
    </table>
  </div>

  <script src="https://www.gstatic.com/firebasejs/4.9.1/firebase.js"></script>
  <script>
    // Initialize Firebase
    var config = {
      apiKey: "AIxxxxxxxxxxxxxxxxxxxxxxxxxxx",
      authDomain: "xxxxxxxxxxxx.firebaseapp.com",
      databaseURL: "https://xxxxxxxxxxxxx.firebaseio.com",
      projectId: "xxxxxxxxxxxxxxxx",
      storageBucket: "xxxxxxxxxxxxx.appspot.com",
      messagingSenderId: "0000000000000000"
    };
    firebase.initializeApp(config);
  </script>

  <script src="https://code.jquery.com/jquery-3.1.0.js"></script>
  <script src="index.js"></script>
  <script src="https://www.gstatic.com/firebasejs/4.12.0/firebase-database.js"></script>

</body>

</html>

推荐答案

您基本上是这样做的:

var storage = firebase.storage().ref();

哪个可以给您 Reference

Which gives you a Reference.

然后您致电:

storage.refFromURL('url_ul')

但是 refFromURL仅在根Storage对象.

But refFromURL is only defined on the root Storage object.

因此,您需要:

var storage = firebase.storage();
storage.refFromURL('url_ul')

这篇关于Firebase refFromURL不是函数的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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